二维数组中对角线的总和

Question

for (row=0; row<SIZE; row++)
    {
        for (col=0; col<SIZE; col++)
        {
            if (row == 0 && col == 0) {
                answer+=my_data[row][col];
            }
            else if ((row)/(col) == 1) //1 is slope of array
            {
                answer+=my_data[row][col];
            }
        }
    }
    printf("The diagonal sum of the 8x8 array is: %i\n",answer);

从...开始到[0,0]结束[8,8]

"从[0,0]开始,对8x8数组内的对角线值求和

我意识到我可以做一个单循环,因为形状只是1:1,但我怎么做才能以防万一我需要总结对角8x10数组？

Answer 1

对角线元素和主对角线仅针对方形矩阵定义.

if rowcount == colcount
  sum = 0
  for i = 0 to rowcount
    sum += matrix[i][i]
  end-for
else
  print Diagonal sum not defined
end-if

对于非方形矩阵,如果要将位置上的元素相等且行号和列号相等,则可以执行以下操作:

sum = 0
for i = 0 to min(rowcount,colcount)
  sum += matrix[i][i]
end-for
print sum