使用 python 将 JSON 值插入到 MySQL 表中

use*_*330 4 python mysql json python-requests

我有一个从requests.get恢复的 JSON 文件

这是我的一些 JSON:

 [{"order":{"id":"B4589B26","status_order_id":5,"status_order_name":"Sent","customer_id":326
"order_products":[{"order_product":{"id":96218,"order_id":96538,"product_id":59320,}}],"customer_email":"user@gmail.com","customer_company":"SARL","customer_name":"user user", .....
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这是我的代码:

token = "xxxx"

r = requests.get('url', auth=('user@gmail.com', token))

mydb = pymysql.connect(host='localhost',
user='root',
passwd='user',
db='ytm_db')

cursor = mydb.cursor()

data = r.json()
json_obj = json.loads(r)

for ord in json_obj["order"]:
    print("id:", ord["id"])
    print("status_id:", ord["status_order_id"])
    print('---')
    cursor.execute("INSERT INTO table_test (id, status_order_id, customer_id) VALUES (%s,%s,%s)", (ord["id"], ord["status_order_id"], ord["customer_id"]))

#close the connection to the database.
mydb.commit()
cursor.close()
print ("Done")
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我有这个错误:

    'not {!r}'.format(s.__class__.__name__))
TypeError: the JSON object must be str, bytes or bytearray, not 'Response'
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Rak*_*esh 5

你不需要这条线json_obj = json.loads(r)r.json()返回一个 json 响应。

前任:

json_obj = r.json()

for ord in json_obj["order"]:
    print("id:", ord["id"])
    print("status_id:", ord["status_order_id"])
    print('---')
    cursor.execute("INSERT INTO table_test (id, status_order_id, customer_id) VALUES (%s,%s,%s)", (ord["id"], ord["status_order_id"], ord["customer_id"]))

#close the connection to the database.
mydb.commit()
cursor.close()
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