Mar*_*oLe 9 unit-testing mocking jasmine karma-jasmine angular
public onSubmit(registerData: RegisterDataModel): void {
this.registrationService.registerWithEmailAndPassword(registerData).then((msg: string[]) =>
this.router.navigate(['/completeSignUp']).then(() => {
msg.forEach(singleMessage => this.notificationService.primary(singleMessage));
}))
.catch((msg) => msg.forEach(singleMessage => {
this.notificationService.danger(singleMessage);
}));
}
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我想测试是否router.navigate在我的方法中调用.现在我想嘲笑我的 service.registerWithEmailAndPasswort承诺但不知何故我不能嘲笑它.
//Stubs
const routerStub: Router = jasmine.createSpyObj('Router', ['navigate']);
const registryStub: RegistrationService = jasmine.createSpyObj('RegistrationService', ['registerWithEmailAndPassword']);
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it('should navigate on promise - success', () => {
(<jasmine.Spy>registryStub.registerWithEmailAndPassword).and.callThrough();
const spy = (<jasmine.Spy>routerStub.navigate);
component.onSubmit({username: null, email: null, password: null, passwordConfirm: null, termsAndCondition: null});
expect(spy).toHaveBeenCalledWith(['/completeSignUp']);
});
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出现的错误是:TypeError: Cannot read property 'then' of undefined
有人如何正确模拟此服务?
我也试图模仿这样的承诺:
(<jasmine.Spy>registryStub.registerWithEmailAndPassword)
.and.returnValue(new Promise(() => Promise.resolve()));
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但它仍然让我感到:
Expected spy Router.navigate to have been called with [ [ '/completeSignUp' ] ] but it was never called.
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小智 8
正如硅魂所提到的那样,你需要router.navigate用一个返回值来嘲笑这个诺言,否则它就会变成一个Promise.reject().通过添加(<jasmine.Spy>routerStub.navigate).and.returnValue(Promise.resolve());单元测试应该没问题.最终的单元测试应如下所示:
it('should navigate on promise - success', fakeAsync(() => {
const spy = (<jasmine.Spy>routerStub.navigate).and.returnValue(Promise.resolve());
(<jasmine.Spy>registryStub.registerWithEmailAndPassword).and.returnValue(Promise.resolve(['test']));
component.onSubmit({username: 'test', email: 'test', password: 'test', passwordConfirm: 'test', termsAndCondition: true});
tick();
expect(spy).toHaveBeenCalledWith(['/completeSignUp']);
}));
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