如何将NSUInteger转换为NSString？

Question

你怎么把一个NSUInteger变成一个NSString？我已经尝试了,但我一直NSString都是0.

NSUInteger NamesCategoriesNSArrayCount = [self.NamesCategoriesNSArray count];  
NSLog(@"--- %d", NamesCategoriesNSArrayCount);  
[NamesCategoriesNSArrayCountString setText:[NSString stringWithFormat:@"%d",    NamesCategoriesNSArrayCount]];  
NSLog(@"=== %d", NamesCategoriesNSArrayCountString);

Answer 1

在使用支持进行编译时arm64,这不会生成警告:

[NSString stringWithFormat:@"%lu", (unsigned long)myNSUInteger];

Answer 2

我希望你NamesCategoriesNSArrayCountString的NSString; 如果是,请使用以下代码行.

NamesCategoriesNSArrayCountString  = [NSString stringWithFormat:@"%d", NamesCategoriesNSArrayCount]];

不是

[NamesCategoriesNSArrayCountString setText:[NSString stringWithFormat:@"%d", NamesCategoriesNSArrayCount]];

Answer 3

编译时arm64,使用以下内容以避免警告:

[NSString stringWithFormat:@"%tu", myNSUInteger];

或者,在您的情况下:

NSUInteger namesCategoriesNSArrayCount = [self.NamesCategoriesNSArray count];  
NSLog(@"--- %tu", namesCategoriesNSArrayCount);  
[namesCategoriesNSArrayCountString setText:[NSString stringWithFormat:@"%tu", namesCategoriesNSArrayCount]];  
NSLog(@"=== %@", namesCategoriesNSArrayCountString);

(另外,提示:变量以小写开头.信息:这里)

Answer 4

您还可以使用:

NSString *rowString = [NSString stringWithFormat: @"%@",  @(row)];

其中row是NSUInteger.