通过XML配置统一字典

vit*_*ali 4 xml dependency-injection inversion-of-control unity-container

如何使用Unity容器通过XML配置字典?这有效:

<register type="System.Collections.Generic.Dictionary[string,int]" >
<constructor>
    <param name="capacity">
    <value value="10" />
    </param>
</constructor>
</register>
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但我需要能够在XML配置中添加元素.

Igo*_*aka 6

上次我尝试这样做时,我不得不使用自定义转换器并为字典值创建自己的解析器.我不记得哪个研究让我在那里,但这里是注册和相应的转换器类.

<type type="IRequestPolicy" mapTo="RequestPolicyCatalog, Assembly">
   <constructor>
     <param name="dictionary" type="System.Collections.Generic.KeyValuePair`2[System.Int32,System.String][], mscorlib">
       <array>
         <value value="1, 'unauthorized'" typeConverter="Assembly.IntStringKeyValueConverter, fore.Core"/>
         <value value="2, 'activation'" typeConverter="Assembly.IntStringKeyValueConverter, Quofore.Core"/>
         <value value="3, 'routing'" typeConverter="Assembly.IntStringKeyValueConverter, Quofore.Core"/>
       </array>
     </param>
   </constructor>
</type>
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public class IntStringKeyValueConverter : System.ComponentModel.TypeConverter {
    public override object ConvertTo(System.ComponentModel.ITypeDescriptorContext context, System.Globalization.CultureInfo culture, object value, Type destinationType) {
        return this.ConvertFrom(context, culture, value);           
    }

    public override bool CanConvertFrom(System.ComponentModel.ITypeDescriptorContext context, Type sourceType) {
        return sourceType == typeof(string);
    }

    public override bool CanConvertTo(System.ComponentModel.ITypeDescriptorContext context, Type destinationType) {
        return destinationType == typeof(KeyValuePair<int, string>);
    }

    public override object ConvertFrom(System.ComponentModel.ITypeDescriptorContext context, System.Globalization.CultureInfo culture, object value) {
        var comma = ((string)value).IndexOf(',');
        if(comma < 0)
            throw new InvalidOperationException("Invalid string, must contain ',' between values");
        var number = int.Parse(((string)value).Substring(0, comma));
        var str = ((string)value).Substring(comma).Trim(new[] { ',', '\'', ' ' });

        return new KeyValuePair<int, string>(number, str);
    }
}
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