std :: function到成员函数

Question

#include <functional>

struct A
{
    int func(int x, int y)
    {
        return x+y;
    }
};

int main()
{

    typedef std::function<int(int, int) > Funcp;
    A a;
    //Funcp func = std:::bind(&A::func, &a);
    Funcp func = std::bind(&A::func, a, std::placeholders::_1);


    return 0;
}

我在上述两个绑定函数中都遇到错误:

 error C2825: '_Fty': must be a class or namespace when followed by '::'

语法错误在哪里？我正在使用visual studio 2010

Answer 1

Funcp func = std::bind(&A::func, &a, std::placeholders::_1, std::placeholders::_2);