Kar*_*yan 2 java arraylist java-8
让我们说,我有一个数组列表:
catalog id--->901
Catalog name --->series277
catalog id--->901
Catalog name --->series277
catalog id--->545
Catalog name --->series285
catalog id--->545
Catalog name --->series285
catalog id--->545
Catalog name --->series285
catalog id--->546
Catalog name --->series685
catalog id--->546
Catalog name --->series685
catalog id--->40962
Catalog name --->series19348
catalog id--->40962
Catalog name --->series19348
catalog id--->40962
Catalog name --->series19348
catalog id--->40962
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从这个列表中,我想找到如下所示的出现次数.
catalog id--->901 -- 2
catalog id--->545 -- 3
catalog id--->546 -- 2
catalog id--->40962 -- 4
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我的目标是,基于id我想要创建循环以进一步迭代的出现次数.
请找到我的Arraylist创建的java代码
List<Catalog> catalogList2 = new ArrayList<Catalog>();
for (SearchHit hit1 : searchHits2)
{
sourceAsMap2 = hit1.getSourceAsMap();
catalog2 = new Catalog();
catalog2.setId(String.valueOf(sourceAsMap2.get("catalog_id")));
catalog2.setCatalog_name(String.valueOf(sourceAsMap2.get("catalog_name")));
catalogList2.add(catalog2);
}
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UPDATE
试图实现以下案例:
for(int i=0;i<catalogList2.size();i++) {
// want to find the number of occurances for catalog.getId()
//Then i want to create a loop based on the number of occurances of catalog id
for(int i=0;i<catalog_id_occurances.size;i++)
{
//Have to do something.
}
}
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您可以使用Streams:
catalogs.stream().collect(
Collectors.groupingBy(Catalog::getId, Collectors.counting()));
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输出:
jshell> catalogList.stream().collect(
...> Collectors.groupingBy(Catalog::getId, Collectors.counting()));
$43 ==> {901=2, 545=3, 546=2, 40962=4}
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- 编辑 -
如果您想进一步操作输出或想要以某种客户格式打印,可以使用以下内容:
catalogList.stream().collect(Collectors.groupingBy(Catalog::getId, Collectors.counting())).entrySet().stream().map(p->"catalog id--->"+p.getKey()+" -- "+p.getValue()).forEach(System.out::println);
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输出:
catalog id--->901 -- 2
catalog id--->545 -- 3
catalog id--->546 -- 2
catalog id--->40962 -- 4
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