将嵌套的序列化数据作为一个整体获取

Aas*_*wat 3 python django django-models django-rest-framework

实际回报

{
"store_product_mapping":{
  "master_product":{
    "name": "abc",
    "description": "xyz"
    }
  }
"selling_price": 445
}
Run Code Online (Sandbox Code Playgroud)

序列化器看起来像:

class GrandParentSerializer(serializers.ModelSerializer):
  class Meta:
  model = Z
  fields = ('name', 'description')

class ParnetSerializer(serializers.ModelSerializer):
  master_product = GrandParentSerializer(many=False, read_only=False)
  class Meta:
  model = Y
  fields = ('master_product',)

class ChildSerializer(serializers.ModelSerializer):
  store_product_mapping = ParnetSerializer(many=False, read_only=False) 
  class Meta:
  model = X
  fields = ('store_product_mapping', 'selling_price')
Run Code Online (Sandbox Code Playgroud)

我使用嵌套rest_framework.serializer.ModelSerializer来序列化多个级别的数据,但作为响应,我需要它是这样的。我需要制作一本新字典并循环更新字典吗?或者有没有捷径可以做同样的事情?

{
"name": xyz
"description": abcd
"price": 10
}
Run Code Online (Sandbox Code Playgroud)

nev*_*ner 5

您可以source像这样使用参数:

class ChildSerializer(serializers.ModelSerializer):
      name = serializers.CharField(source='store_product_mapping.master_product.name') 
      description = serializers.CharField(source='store_product_mapping.master_product.description') 

      class Meta:
          model = X
          fields = ('name', 'description', 'selling_price')
Run Code Online (Sandbox Code Playgroud)