Symfony 4 中的 Guard Authenticator

Question

我正在 Symfony 4 中创建一个简单的登录身份验证系统并使用安全组件 Guard。我的 FormLoginAuthenticator 如下：

<?php
namespace App\Security;

use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\HttpFoundation\RedirectResponse;
use Symfony\Component\Routing\RouterInterface;
use Symfony\Component\Security\Core\Encoder\UserPasswordEncoderInterface;
use Symfony\Component\Security\Core\Exception\BadCredentialsException;
use Symfony\Component\Security\Core\Exception\AuthenticationException;
use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\User\UserProviderInterface;
use Symfony\Component\Security\Core\Authentication\Token\TokenInterface;
use Symfony\Component\Security\Guard\Authenticator\AbstractFormLoginAuthenticator;
use Symfony\Component\Security\Core\Security;

class FormLoginAuthenticator extends AbstractFormLoginAuthenticator
{
    private $router;
    private $encoder;

    public function __construct(RouterInterface $router, UserPasswordEncoderInterface $encoder)
    {
        $this->router = $router;
        $this->encoder = $encoder;
    }

    public function getCredentials(Request $request)
    {
        if ($request->getPathInfo() != '/login_check') {
          return;
        }

        $email = $request->request->get('_email');
        $request->getSession()->set(Security::LAST_USERNAME, $email);
        $password = $request->request->get('_password');

        return [
            'email' => $email,
            'password' => $password,
        ];
    }

    public function getUser($credentials, UserProviderInterface $userProvider)
    {
        $email = $credentials['email'];

        return $userProvider->loadUserByUsername($email);
    }

    public function checkCredentials($credentials, UserInterface $user)
    {
        $plainPassword = $credentials['password'];
        if ($this->encoder->isPasswordValid($user, $plainPassword)) {
            return true;
        }

        throw new BadCredentialsException();
    }

    public function onAuthenticationSuccess(Request $request, TokenInterface $token, $providerKey)
    {
        $url = $this->router->generate('welcome');

        return new RedirectResponse($url);
    }

    public function onAuthenticationFailure(Request $request, AuthenticationException $exception)
    {
       $request->getSession()->set(Security::AUTHENTICATION_ERROR, $exception);

       $url = $this->router->generate('login');

       return new RedirectResponse($url);
    }

    protected function getLoginUrl()
    {
        return $this->router->generate('login');
    }

    protected function getDefaultSuccessRedirectUrl()
    {
        return $this->router->generate('welcome');
    }

    public function supportsRememberMe()
    {
        return false;
    }
}

但它显示以下错误：

(1/1) FatalErrorException 错误：App\Security\FormLoginAuthenticator 类包含 1 个抽象方法，因此必须声明为抽象方法或实现其余方法 (Symfony\Component\Security\Guard\AuthenticatorInterface::supports)

你能给我任何线索，这个类的哪个抽象方法导致了这个错误？

Answer 1

在 FormLoginAuthenticator 类中写入：

public function supports(Request $request)
{
    return 'app_login' === $request->attributes->get('_route')
    && $request->isMethod('POST');
}

'app_login' 是名称控制器登录