如何在ASP.NET MVC中保留未转义的URL参数？

Question

我注意到Stackoverflow登录/注销链接上的returnurl URL参数没有被转义,但是当我尝试将路径作为参数添加到路由时,它会被转义.

所以/ login？returnurl =/questions/ask shows/login？returnurl =%2fquestions%2fask,这有点难看.如何让它不能逃避returnurl值？

这是我在代码中所做的事情:

Html.ActionLink("Login", "Login", "Account", new { returnurl=Request.Path }, null)

Answer 1

如何让它不能逃避returnurl值

怎么样？

var url = Url.Action("Login", "Account", new {returnurl = Request.Path});
var unEncodedUrl = HttpUtility.UrlDecode(url);
Response.Write("<a href='" + unEncodedUrl + "'>...</a>");

确保这是你想要的,URL编码有其目的.

Answer 2

我理解有关编码发生的评论之一是有原因的；这只是一个例外，而不是规则。

这是我整理的，请问如何改进？

    public static string ActionLinkNoEscape(this HtmlHelper html, string linkText, string actionName, string controllerName, object values, object htmlAttributes)
    {
        RouteValueDictionary routeValues = new RouteValueDictionary(values);
        RouteValueDictionary htmlValues = new RouteValueDictionary(htmlAttributes);

        UrlHelper urlHelper = new UrlHelper(html.ViewContext.RequestContext, RouteTable.Routes);
        string url = urlHelper.Action(actionName, controllerName);
        url += "?";
        List<string> paramList = new List<string>();
        foreach (KeyValuePair<string, object> pair in routeValues)
        {
            object value = pair.Value ?? "";
            paramList.Add(String.Concat(pair.Key, "=", Convert.ToString(value, CultureInfo.InvariantCulture)));
        }
        url += String.Join("&", paramList.ToArray());

        TagBuilder builder = new TagBuilder("a");
        builder.InnerHtml = string.IsNullOrEmpty(linkText) ? "" : HttpUtility.HtmlEncode(linkText);
        builder.MergeAttributes<string, object>(htmlValues);
        builder.MergeAttribute("href", url);
        return builder.ToString(TagRenderMode.Normal);
    }