从CosmosDB中文档嵌套数组中的对象中选择值

jas*_*jas 3 azure-cosmosdb azure-cosmosdb-sqlapi

想象我们有一个这样的集合(示例取自 https://www.documentdb.com/sql/demo

{
    "_id" : "19015",
    "description" : "Snacks, granola bars, hard, plain",
    "servings" : [ 
        {
            "amount" : 1,
            "description" : "bar",
            "weightInGrams" : 21
        }, 
        {
            "amount" : 1,
            "description" : "bar (1 oz)",
            "weightInGrams" : 28
        }, 
        {
            "amount" : 1,
            "description" : "bar",
            "weightInGrams" : 25
        }
    ]
}
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我如何在SQL api中查询CosmosDB以获取这样的结果?

{
    "_id" : "19015",
    "servings" : [ 
        {
            "description" : "bar"
        }, 
        {
            "description" : "bar (1 oz)"
        }, 
        {
            "description" : "bar"
        }
    ]
}
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在MongoDB,我会使用这样的查询

db.getCollection('food').find({id: '19015'}, {'servings.description' : 1})
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使用联接等尝试了多个方案

SELECT 
    food.id,
    food.servings.description
FROM food
WHERE food.id = "19015"
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要么

SELECT 
    food.id,
    [{
        description: food.servings[0].description
    }] AS servings
FROM food
WHERE food.id = "19015"
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  • 而不是[0]我尝试过[][$]但不起作用

有人知道我如何以简单的方式解决此问题吗?

Sam*_*hra 6

您可以使用ARRAY(subquery)表达式来实现此目的。这是查询:

SELECT
    food.id,
    ARRAY(SELECT serving.description FROM serving IN food.servings) AS servings
FROM food
WHERE food.id = "19015"
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  • 是的,Cosmos DB最近添加了对子查询的支持。我们目前正在发布文档。 (2认同)

小智 1

通过执行此查询:

select food.id, servings.description
from food join servings in food.servings
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你至少会得到以下结果:

{"id":19015, "description":"bar"}
{"id":19015, "description":"bar (1 oz)"}
{"id":19015, "description":"bar"}
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不是 100% 符合您的预期,但也许是您可以使用的东西!