获取C中的当前时间

Question

我想得到我系统的当前时间.为此,我在C中使用以下代码:

time_t now;
struct tm *mytime = localtime(&now); 
if ( strftime(buffer, sizeof buffer, "%X", mytime) )
{
    printf("time1 = \"%s\"\n", buffer);
}

问题是这段代码给出了一些随机时间.此外,随机时间每次都不同.我想要我系统的当前时间.

Answer 1

从这里复制粘贴:

/* localtime example */
#include <stdio.h>
#include <time.h>

int main ()
{
  time_t rawtime;
  struct tm * timeinfo;

  time ( &rawtime );
  timeinfo = localtime ( &rawtime );
  printf ( "Current local time and date: %s", asctime (timeinfo) );

  return 0;
}

(只需将"void"添加到main()参数列表中,以便在C)中工作

Answer 2

初始化now变量.

time_t now = time(0); // Get the system time

该localtime函数用于将传递的时间值转换time_t为a struct tm,它实际上并不检索系统时间.

Answer 3

简单的方法:

#include <time.h>
#include <stdio.h>

int main(void)
{
    time_t mytime = time(NULL);
    char * time_str = ctime(&mytime);
    time_str[strlen(time_str)-1] = '\0';
    printf("Current Time : %s\n", time_str);

    return 0;
}

Answer 4

为了扩展上面@mingos的答案,我编写了下面的函数来将我的时间格式化为特定的格式([dd mm yyyy hh:mm:ss]).

// Store the formatted string of time in the output
void format_time(char *output){
    time_t rawtime;
    struct tm * timeinfo;

    time ( &rawtime );
    timeinfo = localtime ( &rawtime );

    sprintf(output, "[%d %d %d %d:%d:%d]",timeinfo->tm_mday, timeinfo->tm_mon + 1, timeinfo->tm_year + 1900, timeinfo->tm_hour, timeinfo->tm_min, timeinfo->tm_sec);
}

更多相关信息struct tm,可以发现在这里.

Answer 5

#include<stdio.h>
#include<time.h>

void main()
{
    time_t t;
    time(&t);
    printf("\n current time is : %s",ctime(&t));
}

Answer 6

伙计们,您可以使用此功能获取当前的当地时间.如果你想要gmtime然后使用gmtime函数而不是localtime.干杯

time_t my_time;
struct tm * timeinfo; 
time (&my_time);
timeinfo = localtime (&my_time);
CCLog("year->%d",timeinfo->tm_year+1900);
CCLog("month->%d",timeinfo->tm_mon+1);
CCLog("date->%d",timeinfo->tm_mday);
CCLog("hour->%d",timeinfo->tm_hour);
CCLog("minutes->%d",timeinfo->tm_min);
CCLog("seconds->%d",timeinfo->tm_sec);