假设我有以下表格结构:
t1
-------------
id // row id
userID_follower // this user is a follows another member
userID_following  // other member that this user 
是否可以运行单个查询来组合以下两个:
这个人关注了多少用户
从t1 WHERE userID_follower =".$ myID"中选择COUNT(id).".
有多少用户关注此人
从t1 WHERE userID_following =".$ myID"中选择COUNT(id).
谢谢.
The*_*ter 53
在MySql中,您可以SUM()在条件上使用该函数,因为错误条件将等于0,并且true将等于1:
SELECT SUM(userID_follower = $myID) AS followerCount,
   SUM(userID_following = $myID) AS followingCount
FROM t1
WHERE userID_follower = $myID
   OR userID_following = $myID
Tho*_*mas 10
Hoyle(ISO)解决方案将使用Case表达式:
Select Sum( Case When userID_follower = $myID Then 1 Else 0 End ) As followerCount
    , Sum( Case When userID_following = $myID Then 1 Else 0 End ) As followingCount
From t1
Where userID_follower = $myID
    Or userID_following = $myID
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