Symfony 4-自动装配不起作用

Joa*_*uza 2 php symfony

我有一种将值写入特定实体的表单,并且我试图通过控制器中的函数来编辑信息,这非常简单。

BancoController.php

<?php

namespace App\Controller;

use App\Entity\Banco;
use App\Form\BancoType;
use App\Repository\BancoRepository;
use Doctrine\ORM\EntityManagerInterface;
use Symfony\Component\Form\FormFactoryInterface;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\HttpFoundation\RedirectResponse;
use Symfony\Component\HttpFoundation\Session\Flash\FlashBagInterface;
use Symfony\Component\HttpFoundation\Session\SessionInterface;
use Symfony\Component\Routing\Annotation\Route;
use Symfony\Component\Routing\RouterInterface;
use Symfony\Component\Security\Core\Authorization\AuthorizationCheckerInterface;
use Symfony\Component\HttpKernel\Exception\UnauthorizedHttpException;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Security;
use Symfony\Component\Security\Core\Authentication\Token\Storage\TokenStorageInterface;

class BancoController{

    private $twig;

    private $bancoRepository;

    private $formFactory;

    private $entityManager;

    private $router;

    private $flashBag;

    private $authorizationChecker;

    public function __construct(
        \Twig_Environment $twig, 
        BancoRepository $bancoRepository, 
        FormFactoryInterface $formFactory, 
        EntityManagerInterface $entityManager, 
        RouterInterface $router,
        FlashBagInterface $flashBag,
        AuthorizationCheckerInterface $authorizationChecker
    ){
        $this->twig = $twig;
        $this->bancoRepository = $bancoRepository;
        $this->formFactory = $formFactory;
        $this->entityManager = $entityManager;
        $this->router = $router;
        $this->flashBag = $flashBag;
        $this->authorizationChecker = $authorizationChecker;
    }

    /**
    * @Route("/cadastro/bancos", name="cadastro_banco")
    */
    public function index(TokenStorageInterface $tokenStorage){

        $usuario = $tokenStorage->getToken()->getUser();

        $html = $this->twig->render('bancos/index.html.twig', [
            'bancos' => $this->bancoRepository->findBy(array('usuario' => $usuario))
        ]);

        return new Response($html);
    }

    /**
    * @Route("/banco/{id}", name="editar")
    */
    public function editarBanco(Banco $banco, Request $request) {

        $form = $this->formFactory->create(
            BancoType::class,
            $banco
        );
        $form->handleRequest($request);

        if ($form->isSubmitted() && $form->isValid()){
            $this->entityManager->flush();

            return new RedirectResponse($this->router->generate('cadastro_banco'));
        }

        return new Response(
            $this->twig->render(
                'bancos/cadastro.html.twig',
                ['form' => $form->createView()]
            ));
    }

    /**
    * @Route("/cadastro/cadastrar-banco", name="cadastro_banco-nova")
    */
    public function cadastrar(Request $request, TokenStorageInterface $tokenStorage){

        $usuario = $tokenStorage->getToken()->getUser();

        $banco = new Banco();
        $banco->setUsuario($usuario);

        $form = $this->formFactory->create(BancoType::class, $banco);
        $form->handleRequest($request);

        if ($form->isSubmitted() && $form->isValid()){
            $this->entityManager->persist($banco);
            $this->entityManager->flush();

            return new RedirectResponse($this->router->generate('cadastro_banco'));
        }

        return new Response(
            $this->twig->render(
                'bancos/cadastro.html.twig',
                ['form' => $form->createView()]
        )
        );
    }
}
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问题是,当我访问/ banco / {id}时,出现错误:

"Cannot autowire argument $banco of "App\Controller\BancoController::editarBanco()": it references class "App\Entity\Banco" but no such service exists."
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我的service.yaml都是默认值,因此我猜它应该可以自动运行。实体未显示在bin / console debug:container中。

如果我像这样在services.yaml中手动声明实体

App\Entity\Banco:
    autowire: true
    autoconfigure: true
    public: false
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它可以正常工作,但是现在当我访问/ banco / {id}时,表单将变为空,并且没有数据库中存在的信息,并且如果我键入内容并提交,则数据库中没有任何变化。

如果我转到调试工具栏并检查查询,则似乎在查询登录用户的ID,而不是实体“ Banco”的ID。

顺便说一句,这个实体表有一个FK user_id。也许这就是问题所在?我迷路了,所以我需要一点帮助。我是PHP / Symfony的新手。谢谢

Joa*_*uza 5

好吧,由于某些未知原因sensio/framework-extra-bundle,它没有完全安装。

我刚刚跑步composer require annotations,现在一切正常。

该死的,浪费了2天试图解决这个问题。

谢谢大家 !

  • 仅就信息而言,错误消息有点误导。这确实与自动装配无关。问题在于,如果没有正确安装额外的捆绑软件,则[param conversion](https://symfony.com/doc/master/bundles/SensioFrameworkExtraBundle/annotations/converters.html)进程无法正常工作,因此没有$ banco。 (3认同)