使用OSMNx绘制多条路线

Question

我正在使用OSMNx绘制最短路径路线，但无法找到在同一地图上绘制多个路线的方法。到目前为止，这是我的代码，

route_list = []
for i in range(len(pick_drop_outliers_ratio)):
coords = pick_drop_outliers_ratio["Pickup_Points"][i]
count = pick_drop_outliers_ratio["Count"][i]
print("i: ", i, " count: ", count)
if(count>9):
    coords = literal_eval(coords)
    pickup_lat = (coords[0][0])
    pickup_lon = (coords[0][1])
    dropoff_lat = (coords[1][0])
    dropoff_lon = (coords[1][1])
    orig_node = ox.get_nearest_node(G, (pickup_lat, pickup_lon))
    dest_node = ox.get_nearest_node(G, (dropoff_lat, dropoff_lon))
    route = nx.shortest_path(G, orig_node, dest_node, weight='length')
    route_list.append(route)
fig, ax = ox.plot_graph_route(G, route_list, node_size=0)

我希望在同一地图上的route_list中以不同的颜色绘制每条路线。由于OSMNx中没有内置功能，有没有办法做到这一点？

我发现解决方案是“绘制图表，然后使用matplotlib在顶部手动添加路由”。但是无法实现。

Answer 1

值得注意的是，此功能自v0.8.2起已存在于OSMnx中。此处以绘制具有各自颜色的多条路线的示例。

import networkx as nx
import osmnx as ox
ox.config(log_console=True, use_cache=True)

G = ox.graph_from_place('Piedmont, CA, USA', network_type='drive')

# pick 4 random nodes as origins/destinations for the 2 routes
orig1 = list(G.nodes())[0]
dest1 = list(G.nodes())[-1]
orig2 = list(G.nodes())[50]
dest2 = list(G.nodes())[-50]

# calculate shortest paths for the 2 routes
route1 = nx.shortest_path(G, orig1, dest1, weight='length')
route2 = nx.shortest_path(G, orig2, dest2, weight='length')

# create route colors
rc1 = ['r'] * (len(route1) - 1)
rc2 = ['b'] * len(route2)
rc = rc1 + rc2
nc = ['r', 'r', 'b', 'b']

# plot the routes
fig, ax = ox.plot_graph_routes(G, [route1, route2], route_color=rc, orig_dest_node_color=nc, node_size=0)