Bro*_*ams 6 sql t-sql sql-server sql-server-2017
我有表格按类别列出用户的销售额(每个销售至少有一个,可能有几个类别).
我能得到的最高类别的用户,但我需要的用户统计数据都他/她的前N类和余数.
我将问题归结为MCVE,如下所示......
MCVE 数据摘要:
Salesman SaleID Amount Categories
-------- ------ ------ ------------------------------
1 1 2 Service
2 2 2 Software, Support_Contract
2 3 3 Service
2 4 1 Parts, Service, Software
2 5 3 Support_Contract
2 6 4 Promo_Gift, Support_Contract
2 7 -2 Rebate, Support_Contract
3 8 2 Software, Support_Contract
3 9 3 Service
3 10 1 Parts, Software
3 11 3 Support_Contract
3 12 4 Promo_Gift, Support_Contract
3 13 -2 Rebate, Support_Contract
MCVE设置SQL:
CREATE TABLE Sales ([Salesman] int, [SaleID] int, [Amount] int);
CREATE TABLE SalesTags ([SaleID] int, [TagId] int);
CREATE TABLE Tags ([TagId] int, [TagName] varchar(100) );
INSERT INTO Sales
([Salesman], [SaleID], [Amount])
VALUES
(1, 1, 2), (2, 6, 4), (3, 10, 1),
(2, 2, 2), (2, 7, -2), (3, 11, 3),
(2, 3, 3), (3, 8, 2), (3, 12, 4),
(2, 4, 1), (3, 9, 3), (3, 13, -2),
(2, 5, 3)
;
INSERT INTO SalesTags
([SaleID], [TagId])
VALUES
(1, 3), (6, 4), (10, 1),
(2, 1), (6, 5), (10, 2),
(2, 4), (7, 4), (11, 4),
(3, 3), (7, 6), (12, 4),
(4, 1), (8, 1), (12, 5),
(4, 2), (8, 4), (13, 4),
(4, 3), (9, 3), (13, 6),
(5, 4)
;
INSERT INTO Tags
([TagId], [TagName])
VALUES
(1, 'Software'),
(2, 'Parts'),
(3, 'Service'),
(4, 'Support_Contract'),
(5, 'Promo_Gift'),
(6, 'Rebate')
;
看到这个SQL小提琴,我可以得到用户的前N个标签,如:
WITH usersSales AS ( -- actual base CTE is much more complex
SELECT s.SaleID
, s.Amount
FROM Sales s
WHERE s.Salesman = 2
)
SELECT Top 3 -- N can be 3 to 10
t.TagName
, COUNT (us.SaleID) AS tagSales
, SUM (us.Amount) AS tagAmount
FROM usersSales us
INNER JOIN SalesTags st ON st.SaleID = us.SaleID
INNER JOIN Tags t ON t.TagId = st.TagId
GROUP BY t.TagName
ORDER BY tagAmount DESC
, tagSales DESC
, t.TagName
- 显示用户的最高类别:
按此顺序,对于用户2.(和Support_Contract,Promo_Gift,用户3的软件.)
但是,对于N = 3,需要的结果是:
用户2:
Top Category Amount Number of Sales
---------------- ------ ---------------
Support Contract 7 4
Service 4 2
Promo Gift 0 0
- All Others - 0 0
============================================
Totals 11 6
用户3:
Top Category Amount Number of Sales
---------------- ------ ---------------
Support Contract 7 4
Promo_Gift 0 0
Software 1 1
- All Others - 3 1
============================================
Totals 11 6
哪里:
- All Others -集团.我如何汇总这样的结果？
请注意,这是在MS SQL-Server 2017上运行的,我无法更改表架构.
这是一种方法。逐步、逐个 CTE 运行查询并检查中间结果以了解其工作原理。
这不是最有效的方法，因为我最终将表连接到自身以消除之前汇总的销售额，但我目前不知道如何避免它。
WITH usersSales
AS
( -- actual base CTE is much more complex
SELECT
s.SaleID
, s.Amount
FROM Sales s
WHERE s.Salesman = 2
)
,CTE_Sums
AS
(
SELECT
t.TagName
,us.Amount
,us.SaleID
,SUM(us.Amount) OVER (PARTITION BY t.TagName) AS TagAmount
,COUNT(*) OVER (PARTITION BY t.TagName) AS TagSales
FROM
usersSales us
INNER JOIN SalesTags st ON st.SaleID = us.SaleID
INNER JOIN Tags t ON t.TagId = st.TagId
)
,CTE_Rank
AS
(
SELECT
TagName
,Amount
,SaleID
,TagAmount
,TagSales
,DENSE_RANK() OVER (ORDER BY TagAmount DESC, TagSales DESC, TagName) AS rnk
FROM CTE_Sums
)
,CTE_Final
AS
(
SELECT
Main.TagName
,Main.Amount
,Main.SaleID
,Main.TagAmount
,Main.TagSales
,Main.rnk
,ISNULL(A.FinalTagAmount, 0) AS FinalTagAmount
,A.FinalTagSales
FROM
CTE_Rank AS Main
OUTER APPLY
(
SELECT
SUM(Detail.Amount) AS FinalTagAmount
,COUNT(*) AS FinalTagSales
FROM CTE_Rank AS Detail
WHERE
Detail.rnk = Main.rnk
AND Detail.SaleID NOT IN
(
SELECT PrevRanks.SaleID
FROM CTE_Rank AS PrevRanks
WHERE PrevRanks.rnk < Detail.rnk
)
) AS A
)
SELECT
TagName
,MIN(FinalTagAmount) AS FinalTagAmount
,MIN(FinalTagSales) AS FinalTagSales
,rnk
,0 AS SortOrder
FROM CTE_Final
WHERE rnk <= 3
GROUP BY
TagName
,rnk
UNION ALL
SELECT
'- All Others -' AS TagName
,SUM(FinalTagAmount) AS FinalTagAmount
,SUM(FinalTagSales) AS FinalTagSales
,0 AS rnk
,1 AS SortOrder
FROM CTE_Final
WHERE rnk > 3
ORDER BY
SortOrder
,rnk
;
CTE_Rank
暂时不要对行进行分组和求和，而是使用窗口聚合来获取每个标签的排名。稍后我们将需要SaleID具有单独金额的单独行 ( ) 来过滤正在使用的行。
+------------------+--------+--------+-----------+----------+-----+
| TagName | Amount | SaleID | TagAmount | TagSales | rnk |
+------------------+--------+--------+-----------+----------+-----+
| Support Contract | -2 | 7 | 7 | 4 | 1 |
| Support Contract | 3 | 5 | 7 | 4 | 1 |
| Support Contract | 4 | 6 | 7 | 4 | 1 |
| Support Contract | 2 | 2 | 7 | 4 | 1 |
| Service | 1 | 4 | 4 | 2 | 2 |
| Service | 3 | 3 | 4 | 2 | 2 |
| Promo Gift | 4 | 6 | 4 | 1 | 3 |
| Software | 1 | 4 | 3 | 2 | 4 |
| Software | 2 | 2 | 3 | 2 | 4 |
| Parts | 1 | 4 | 1 | 1 | 5 |
| Rebate | -2 | 7 | -2 | 1 | 6 |
+------------------+--------+--------+-----------+----------+-----+
CTE_最终
OUTER APPLY通过过滤排名较高的标签中遇到的那些销售来进行主要计算。
+------------------+--------+--------+-----------+----------+-----+----------------+---------------+
| TagName | Amount | SaleID | TagAmount | TagSales | rnk | FinalTagAmount | FinalTagSales |
+------------------+--------+--------+-----------+----------+-----+----------------+---------------+
| Support Contract | -2 | 7 | 7 | 4 | 1 | 7 | 4 |
| Support Contract | 3 | 5 | 7 | 4 | 1 | 7 | 4 |
| Support Contract | 4 | 6 | 7 | 4 | 1 | 7 | 4 |
| Support Contract | 2 | 2 | 7 | 4 | 1 | 7 | 4 |
| Service | 1 | 4 | 4 | 2 | 2 | 4 | 2 |
| Service | 3 | 3 | 4 | 2 | 2 | 4 | 2 |
| Promo Gift | 4 | 6 | 4 | 1 | 3 | 0 | 0 |
| Software | 1 | 4 | 3 | 2 | 4 | 0 | 0 |
| Software | 2 | 2 | 3 | 2 | 4 | 0 | 0 |
| Parts | 1 | 4 | 1 | 1 | 5 | 0 | 0 |
| Rebate | -2 | 7 | -2 | 1 | 6 | 0 | 0 |
+------------------+--------+--------+-----------+----------+-----+----------------+---------------+
查询结果
只需将排名前 3 的标签加上所有其他标签放在一起即可。
+------------------+----------------+---------------+-----+-----------+
| TagName | FinalTagAmount | FinalTagSales | rnk | SortOrder |
+------------------+----------------+---------------+-----+-----------+
| Support Contract | 7 | 4 | 1 | 0 |
| Service | 4 | 2 | 2 | 0 |
| Promo Gift | 0 | 0 | 3 | 0 |
| - All Others - | 0 | 0 | 0 | 1 |
+------------------+----------------+---------------+-----+-----------+
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