如何将样式应用于带有样式组件的react-burger-menu按钮?

bas*_*sse 8 javascript reactjs styled-components

我想styled-components在React应用程序中使用它来创建一个菜单组件,该菜单组件在同一文件中包含样式,从而使其变得非常模块化。我正在使用react-burger-menu菜单。如果我BurgerMenu使用如下样式包装所有样式div(从react-burger-menuREADME.md 复制的样式),则一切正常:

import React from 'react';
import { slide as BurgerMenu } from 'react-burger-menu';
import styled from 'styled-components';


const StyledBurgerMenu = styled.div`
  /* Position and sizing of burger button */
  .bm-burger-button {
    position: fixed;
    width: 36px;
    height: 30px;
    left: 36px;
    top: 36px;
  }

  /* Color/shape of burger icon bars */
  .bm-burger-bars {
    background: #373a47;
  }

  /* Position and sizing of clickable cross button */
  .bm-cross-button {
    height: 24px;
    width: 24px;
  }

  /* Color/shape of close button cross */
  .bm-cross {
    background: #bdc3c7;
  }

  /* General sidebar styles */
  .bm-menu {
    background: #373a47;
    padding: 2.5em 1.5em 0;
    font-size: 1.15em;
  }

  /* Morph shape necessary with bubble or elastic */
  .bm-morph-shape {
    fill: #373a47;
  }

  /* Wrapper for item list */
  .bm-item-list {
    color: #b8b7ad;
    padding: 0.8em;
  }

  /* Individual item */
  .bm-item {
    display: inline-block;
  }

  /* Styling of overlay */
  .bm-overlay {
    background: rgba(0, 0, 0, 0.3);
  }
`;


export class Menu extends React.Component {
  showSettings(event) {
    event.preventDefault();
  }

  render() {
    return (
      <StyledBurgerMenu>
        <BurgerMenu>
          <a id="home" className="menu-item" href="/">Home</a>
          <a id="about" className="menu-item" href="/about">About</a>
        </BurgerMenu>
      </StyledBurgerMenu>
    );
  }
}

export default Menu;
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现在,这当然完全可以。然而,要汲取教训,让事情变得更优雅一点,我想摆脱嵌套的BurgerMenu内部StyledBurgerMenu通过将前者styled()。但是,这会导致汉堡按钮的样式没有设置(根据文档,它在整个屏幕上都透明覆盖,因此我可以单击任意位置以打开菜单,看看其他所有样式均正确设置)。是否可以以这种方式设置汉堡按钮的样式,或者我必须使用外部按钮div?这是我尝试解决此问题的方法:

import React from 'react';
import { slide as BurgerMenu } from 'react-burger-menu';
import styled from 'styled-components';


const StyledBurgerMenu = styled(BurgerMenu)`
  /* Position and sizing of burger button */
  .bm-burger-button {
    position: fixed;
    width: 36px;
    height: 30px;
    left: 36px;
    top: 36px;
  }

  /* Color/shape of burger icon bars */
  .bm-burger-bars {
    background: #373a47;
  }

  /* Position and sizing of clickable cross button */
  .bm-cross-button {
    height: 24px;
    width: 24px;
  }

  /* Color/shape of close button cross */
  .bm-cross {
    background: #bdc3c7;
  }

  /* General sidebar styles */
  .bm-menu {
    background: #373a47;
    padding: 2.5em 1.5em 0;
    font-size: 1.15em;
  }

  /* Morph shape necessary with bubble or elastic */
  .bm-morph-shape {
    fill: #373a47;
  }

  /* Wrapper for item list */
  .bm-item-list {
    color: #b8b7ad;
    padding: 0.8em;
  }

  /* Individual item */
  .bm-item {
    display: inline-block;
  }

  /* Styling of overlay */
  .bm-overlay {
    background: rgba(0, 0, 0, 0.3);
  }
`;


export class Menu extends React.Component {
  showSettings(event) {
    event.preventDefault();
  }

  render() {
    return (
      <StyledBurgerMenu>
        <a id="home" className="menu-item" href="/">Home</a>
        <a id="about" className="menu-item" href="/about">About</a>
      </StyledBurgerMenu>
    );
  }
}

export default Menu;
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谢谢!

小智 0

由于样式组件的工作方式,这是不可能的

样式应用于子div,而不是外部div: 链接到react-burger-menu中的代码