从 Java 10.0 NullPointer 开始，同时搜索持久性 - JPA eclipselink 2.6.5

Question

我使用 eclipselink 2.6.5 的一些 EJB 实体作为 Rest 服务（TomEE 服务器中的 Jersy）。

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使用jdk-1.8它工作得很好，但是使用新的jdk-10.0现在我在搜索持久性时遇到了NullPointerException。

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我的 JPA 环境是否存在错误或不匹配？

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谢谢

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史蒂芬

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Exception in thread "main" Local Exception Stack: \nException [EclipseLink-30005] (Eclipse Persistence Services - 2.6.5.v20170607-b3d05bd): org.eclipse.persistence.exceptions.PersistenceUnitLoadingException\n    Exception Description: An exception was thrown while searching for persistence archives with ClassLoader: jdk.internal.loader.ClassLoaders$AppClassLoader@41906a77\n    Internal Exception: java.lang.NullPointerException\n        at org.eclipse.persistence.exceptions.PersistenceUnitLoadingException.exceptionSearchingForPersistenceResources(PersistenceUnitLoadingException.java:127)\n        at org.eclipse.persistence.jpa.PersistenceProvider.createEntityManagerFactoryImpl(PersistenceProvider.java:115)\n        at org.eclipse.persistence.jpa.PersistenceProvider.createEntityManagerFactory(PersistenceProvider.java:188)\n        at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:79)\n        at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:54)\n        at de.company.test.simulation.session.MySimulationService.<init>(MySimulationService.java:50)\n        at de.company.test.simulation.controller.MyController.<init>(MyController.java:81)\n        at de.company.test.simulation.MySimulationLauncher.main(MySimulationLauncher.java:156)\n    Caused by: java.lang.NullPointerException\n        at org.eclipse.persistence.internal.jpa.EntityManagerSetupImpl.predeploy(EntityManagerSetupImpl.java:2030)\n        at org.eclipse.persistence.internal.jpa.deployment.JPAInitializer.callPredeploy(JPAInitializer.java:100)\n        at org.eclipse.persistence.jpa.PersistenceProvider.createEntityManagerFactoryImpl(PersistenceProvider.java:104)\n

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我的坚持.xml

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http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd" \n version="2.1">

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<persistence-unit name="myUnitName" transaction-type="RESOURCE_LOCAL">\n    <provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>\n    <class>de.company.test.simulation.entities.ProjectEntity</class>\n\n    <exclude-unlisted-classes>false</exclude-unlisted-classes>\n    <properties>\n        <property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver" />\n        <property name="javax.persistence.jdbc.url" value="jdbc:mysql://mysql.mediatransfer.de/dbName?useUnicode=true&useJDBCCompliantTimezoneS\xe2\x80\x8c\xe2\x80\x8bhift=true&useLegacyDatetimeCode=false&serverTimezone=UTC" />\n        <property name="javax.persistence.jdbc.user" value="userName" />\n        <property name="javax.persistence.jdbc.password" value="****" />\n\n        <!-- EclipseLink should create the database schema automatically -->\n        <property name="eclipselink.ddl-generation" value="none" />\n        <property name="eclipselink.ddl-generation.output-mode" value="database" />\n        <property name="eclipselink.logging.level" value="SEVERE" />\n    </properties>\n</persistence-unit>\n

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下面是我的 Web 应用程序 ProjectEntity 中的实体示例。\n这在 java 1.8 中对我来说效果很好。

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\n\n @Entity(name = "ProjectEntity")\n @Table(name = "project")\n 公共类 ProjectEntity 实现可序列化 {\n @Id\n @GenerateValue(strategy = GenerationType.IDENTITY)\n @ Column(name = "id", nullable = false, unique = true, updateable = false)\n 私有整数 id; \n @Column(name = "project_name", nullable = false, length = 256)\n @NotNull\n private String 项目名称; \n public ProjectEntity() {}\n //\n\n..\n

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Answer 1

在我遇到同样的问题后，升级到 EclipseLink 2.7.3 解决了我的问题。