Strategy.OAuth2Strategy.parseErrorResponse 中的错误 - NodeJS 通行证 google oauth2.0

Kon*_*owy 7 node.js google-login express google-oauth passport.js

我正在尝试使用护照和谷歌护照-google-oauth20 在 Node.js 中嵌入谷歌身份验证。问题是,当 google 回调路由打开时,我得到:

Error
at Strategy.OAuth2Strategy.parseErrorResponse (E:\Programowanie\NodeJS\Hydronide\node_modules\passport-oauth2\lib\strategy.js:329:12)
at Strategy.OAuth2Strategy._createOAuthError (E:\Programowanie\NodeJS\Hydronide\node_modules\passport-oauth2\lib\strategy.js:376:16)
at E:\Programowanie\NodeJS\Hydronide\node_modules\passport-oauth2\lib\strategy.js:166:45
at E:\Programowanie\NodeJS\Hydronide\node_modules\oauth\lib\oauth2.js:191:18
at passBackControl (E:\Programowanie\NodeJS\Hydronide\node_modules\oauth\lib\oauth2.js:132:9)
at IncomingMessage.<anonymous> (E:\Programowanie\NodeJS\Hydronide\node_modules\oauth\lib\oauth2.js:157:7)
at emitNone (events.js:110:20)
at IncomingMessage.emit (events.js:207:7)
at endReadableNT (_stream_readable.js:1059:12)
at _combinedTickCallback (internal/process/next_tick.js:138:11)
at process._tickCallback (internal/process/next_tick.js:180:9)
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我(或多或少)遵循本教程。这是我的代码:Routes(以“/auth”开头)

'use strict'

const passport = require('passport')
const router = require('express').Router()

router.get(
  '/google',
  (req, res, next) => {
    if (req.query.return) {
      req.session.oauth2return = req.query.return
    }
    next()
  },
  passport.authenticate('google', { scope: ['email', 'profile'] })
)

router.get(
  '/google/callback',
  passport.authenticate('google'),
  (req, res) => {
    const redirect = req.session.oauth2return || '/';
    delete req.session.oauth2return;
    res.redirect(redirect);
  }
);

module.exports = router
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有一个passport配置:

'use strict'
const passport = require('passport')
const keys = require('./keys')
const GoogleStrategy = require('passport-google-oauth20').Strategy
const userController = require('../controllers/user-controller')

const passportConfig = {
  clientID: keys.google.clientId,
  clientSecret: keys.google.clientSecret,
  callbackURL: 'auth/google/callback',
  accessType: 'offline'
}

passport.use(new GoogleStrategy(passportConfig,
  (accessToken, refreshToken, profile, done) => {
  console.log(accessToken, refreshToken, profile, done)
  userController.getUserByExternalId('google', profile.id)
  .then(user => {
    if (!user) {
      userController.createUser(profile, 'google')
      .then(user => {
        return done(null, user)
      })
      .catch(err => {
        return done(err)
      })
    }
    return done(null, user)
  })
  .catch(err => {
    return done(err)
  })
}))

passport.serializeUser((user, cb) => {
  cb(null, user)
})
passport.deserializeUser((obj, cb) => {
  cb(null, obj)
})
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正如您所看到的,我在新的 GoogleStrategy 第二个参数函数中添加了 console.log,但它永远不会触发。

//编辑我注意到require('passport-google-oauth20').Strategy我使用了require('passport-google-oauth20'). 但是修复它并没有改变任何东西,仍然是同样的错误。我可以添加一个问题的是,在我的主要失败中,我调用

// sets passport config
require('./config/jwt-auth')
require('./config/google-auth')

// initialize passport
app.use(passport.initialize())
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所以我不指望那里有什么问题。

小智 6

您必须在策略的 callbackURL 部分指定完整的 url:例如:如果在本地运行代码时localhost:3000使用如下代码:

passport.use(new googleStrategy({
    clientID:keys.clientID,
    clientSecret:keys.clientSecret,
    callbackURL:'auth/google/callback'
},(accessToken,refreshToken, profile,done)=>{
    console.log(accessToken);
    console.log(refreshToken);
    console.log(profile);
}
));

app.get('/auth',passport.authenticate('google',{

    scope:['profile','email']
}));
app.get('/auth/google/callback', 
  passport.authenticate('google'));
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上面的代码肯定会抛出一个 TokenError: Bad request。您必须传递完整的 URl 才能获得如下所示的最终代码:

passport.use(new googleStrategy({
    clientID:keys.clientID,
    clientSecret:keys.clientSecret,
    callbackURL:'http://localhost:3000/auth/google/callback'
},(accessToken,refreshToken, profile,done)=>{
    console.log(accessToken);
    console.log(refreshToken);
    console.log(profile);
}
));

app.get('/auth',passport.authenticate('google',{
    scope:['profile','email']
}));

app.get('/auth/google/callback', 
  passport.authenticate('google'));
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