ASP.NET MVC强类型ViewModel - 组合创建/列表视图

Question

通过创建一个简单的Bug/Feature跟踪系统,我正在学习ASP.NET MVC和Entity Framework Code First,LINQ.我想通过让用户提交上面的表单并将提交的内容显示在下面来模仿Twitter界面.我不确定如何构建强类型视图和所述模型.我想将我的创建和索引视图合并到一个视图中,问题是创建采用单一类型Entry(Pylon.Models.Entry),而索引采用入口(IEnumerable<Pylon.Models.Entry>)的IEnumerable .下面是我的viewmodel类和Display视图.我只是从"创建"和"索引"视图中复制了脚手架生成的代码,显然混合不同的模型会导致运行时错误,从而导致视图被破坏.我的问题是如何重组视图.

// Entry ViewModel
public class EntryViewModel
{
    public Entry Entry { get; set; }
    public IEnumerable<Entry> Entries { get; set; }
}

---

@* Display View *@

@model ?

@{
    ViewBag.Title = "Display";
}

<hr />

@using (Html.BeginForm())
{
    @Html.ValidationSummary(true)
    <fieldset>
        <legend>Entry</legend>

        <div class="editor-label">
            @Html.LabelFor(model => model.Description)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.Description)
            @Html.ValidationMessageFor(model => model.Description)
        </div>

        <div class="editor-label">
            @Html.LabelFor(model => model.OpenDate)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.OpenDate)
            @Html.ValidationMessageFor(model => model.OpenDate)
        </div>

        <div class="editor-label">
            Paradigm
        </div>
        <div class="editor-field">
            @Html.DropDownListFor(model => model.ParadigmId, ((IEnumerable<Pylon.Models.Paradigm>)ViewBag.PossibleParadigms).Select(option => new SelectListItem
        {
            Text = (option == null ? "None" : option.Name),
            Value = option.ParadigmId.ToString(),
            Selected = (Model != null) && (option.ParadigmId == Model.ParadigmId)
        }), "Choose...")
            @Html.ValidationMessageFor(model => model.ParadigmId)
        </div>

        <p>
            <input type="submit" value="Create" />
        </p>
    </fieldset>
}

<hr />

<table>
    <tr>
        <th></th>
        <th>
            Description
        </th>
        <th>
            OpenDate
        </th>
        <th>
            Type
        </th>
    </tr>

@foreach (var item in Model) {
    <tr>
        <td>
            @item.Description
        </td>
        <td>
            @String.Format("{0:d}", item.OpenDate)
        </td>
        <td>
            @(item.Paradigm == null ? "None" : item.Paradigm.Name)
        </td>
    </tr>
}

</table>

任何指针或更好的教程/工作代码都会很棒.

Answer 1

进行以下更改.

1. 设置@model EntryViewModel在视图的顶部.
2. 对于创建表单,更改model => model.Description为model => model.Entry.Description,所以model替换为model.Entry
3. 对于列表模板,请执行以下更改. @foreach (var item in Model.Entries )