我正在从API中提取数据,这些数据为我提供了一些JSON信息.但是,其中一个值给了我:
{X0=80,X1=80,X2=80,X3=80,X4=80,X5=80,X6=80,X7=80,X8=80,X9=80,X10=80,X11=80,X12=80,X13=80,X14=80,X15=80,X16=80,X17=80,X18=80,X19=80,X20=80,X21=80,X22=80,X23=80,X24=80,X25=80,X26=80,X27=80,X28=80,X29=80,X30=80,X31=80,X32=80,X33=80,X34=80,X35=80,X36=80,X37=80,X38=80,X39=80,X40=80,X41=80,X42=80,X43=80,X44=80,X45=80,X46=80,X47=80,X48=80,X49=80,X50=80,X51=80,X52=80,X53=80,X54=80,X55=80,X56=80,X57=80,X58=80,X59=80,X60=80,X61=80,X62=80}
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我试图解码它以用于C#控制台应用程序(.NET).我的主要问题是,将这个字符串提取到字典或数组中的最佳方法是什么?我不确定我是否有正确的措辞,所以如果我错了请纠正我!
谢谢!
你可以使用LINQ的使用Trim,Split,Select,ToDictionary
var result = json.Trim('{', '}')
.Split(',')
.Select(x => x.Split('='))
.ToDictionary(x => x[0], x => int.Parse(x[1]));
Console.WriteLine(string.Join("\r\n", result.Select(x => x.Key + " : " + x.Value)));
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只因为我很无聊
Mode : Release (64Bit)
Test Framework : .NET Framework 4.7.1
Operating System : Microsoft Windows 10 Pro
Version : 10.0.17134
CPU Name : Intel(R) Core(TM) i7-3770K CPU @ 3.50GHz
Description : Intel64 Family 6 Model 58 Stepping 9
Cores (Threads) : 4 (8) : Architecture : x64
Clock Speed : 3901 MHz : Bus Speed : 100 MHz
L2Cache : 1 MB : L3Cache : 8 MB
Benchmarks Runs : Inputs (1) * Scales (3) * Benchmarks (3) * Runs (100) = 900
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结果
--- Random Set ----------------------------------------------------------------------
| Value | Average | Fastest | Cycles | Garbage | Test | Gain |
--- Scale 100 -------------------------------------------------------- Time 0.229 ---
| Split | 0.058 ms | 0.043 ms | 207,064 | 48.000 KB | Base | 0.00 % |
| JsonReplace | 0.077 ms | 0.064 ms | 273,556 | 24.000 KB | Pass | -32.38 % |
| Regex | 0.270 ms | 0.235 ms | 950,504 | 80.000 KB | Pass | -364.87 % |
--- Scale 1,000 ------------------------------------------------------ Time 0.633 ---
| Split | 0.490 ms | 0.446 ms | 1,718,180 | 495.102 KB | Base | 0.00 % |
| JsonReplace | 0.671 ms | 0.596 ms | 2,352,043 | 195.078 KB | Pass | -36.86 % |
| Regex | 2.544 ms | 2.293 ms | 8,897,994 | 731.125 KB | Pass | -419.00 % |
--- Scale 10,000 ----------------------------------------------------- Time 5.005 ---
| Split | 5.247 ms | 4.673 ms | 18,363,748 | 4.843 MB | Base | 0.00 % |
| JsonReplace | 6.782 ms | 5.488 ms | 23,721,593 | 1.829 MB | Pass | -29.25 % |
| Regex | 31.840 ms | 27.008 ms | 111,277,134 | 6.637 MB | Pass | -506.80 % |
-------------------------------------------------------------------------------------
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数据
private string GenerateData(int scale)
{
var ary = Enumerable.Range(0, scale)
.Select(x => $"X{x}={Rand.Next()}")
.ToList();
return $"{{{string.Join(",", ary)}}}";
}
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分裂
public class Split : Benchmark<string, Dictionary<string,int>>
{
protected override Dictionary<string,int> InternalRun()
{
return Input.Trim('{', '}')
.Split(',')
.Select(x => x.Split('='))
.ToDictionary(x => x[0], x => int.Parse(x[1]));
}
}
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正则表达式
归功于emsimpson92使用Cast
public class Regex : Benchmark<string, Dictionary<string,int>>
{
protected override Dictionary<string,int> InternalRun()
{
var regex = new System.Text.RegularExpressions.Regex("(?<key>[^,]+)=(?<value>[^,]+)");
var matchCollection = regex.Matches(Input.Trim('{', '}'));
return matchCollection.Cast<Match>()
.ToDictionary(
x => x.Groups["key"].Value,
x => int.Parse(x.Groups["value"].Value));
}
}
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JsonReplace
归功于Hanzalah Adalan Modified与之合作string.replace
public unsafe class JsonReplace : Benchmark<string, Dictionary<string,int>>
{
protected override Dictionary<string,int> InternalRun()
{
return JsonConvert.DeserializeObject<Dictionary<string,int>>(Input.Replace("=", ":"));
}
}
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其他资源
返回一个新字符串,其中删除当前String对象中一组指定字符的所有前导和尾随出现.
String.Split方法(String [],StringSplitOptions)
根据数组中的字符串将字符串拆分为子字符串.您可以指定子字符串是否包含空数组元素.
Enumerable.Select方法(IEnumerable,Func)
将序列的每个元素投影到新表单中.
Enumerable.ToDictionary方法(IEnumerable,Func)
根据指定的键选择器函数从IEnumerable创建一个Dictionary.