在java中计算两次给定时间的差异b/w

Question

我试图计算给定两次之间的差异,我发现它有一些问题.假设我们有时间值是"11:AM"和10:00 AM".我能够计算但是AM,PM有点混乱.提前感谢

我使用以下代码:

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;

public class StringToDate {

public static String timeDiff(String time1, String time2) {
    String Time = null;
    int difference;
    String a1 = time1.substring(6);
    String a2 = time2.substring(6);

    try {
        // Define a date format the same as the expected input
        SimpleDateFormat sdf = new SimpleDateFormat("HH:mm a");
        // Get time values of the date objects
        long l1 = sdf.parse(time1).getTime();
        long l2 = sdf.parse(time2).getTime();
        difference = (int) (l2 - l1);
        difference = (difference < 0 ? -difference : difference) / 60000;
        if (difference > 60) {
            int Hour = difference / 60;
            int Mins = difference % 60;
            if (Mins == 0)
                Time = Hour + " Hours";
            else
                Time = Hour + " Hours" + " " + Mins + " Mins";
        } else {
            Time = difference + " " + "Mins";
        }
    } catch (ParseException e) {
        e.printStackTrace();
    }
    return Time;
}

public static void main(String[] args) {
    String diff = StringToDate.timeDiff("10:00 AM", "01:00 PM");
    System.out.println("Difference: " + diff);
}

}

Answer 1

您可以获取开始和结束时间的日期对象.然后以毫秒计算并减去时间.

Millis的差异= endDate.getTime() - startDate.getTime()

将差异转换为小时/分钟.