Django FormView 在 success_url 中传递 pk

Question

假设我有以下 FormView，并且我想item.pk在提交表单后将其传递给其他视图。我想我必须编辑，get_success_url()但我什至不知道如何item.pk获取form_valid()：

模型.py

from django.db import models

class Book(models.Model):
    field1 = models.CharField(max_length=32)
    field2 = models.CharField(max_length=32)
    field3 = models.CharField(max_length=32)

    def __str__(self):
        return self.field1

表格.py

from django import forms
from .models import Book

class SomeForm(forms.ModelForm):

    field_order = ['field3', 'field2', 'field1']

    class Meta:
        model = Book
        fields = ['field1', 'field2', 'field3']

视图.py

from django.shortcuts import render
from django.views.generic.edit import FormView
from .forms import SomeForm

class SomeView(FormView):
    form_class = SomeForm
    template_name = 'appname/form.html'
    success_url = reverse_lazy('somewhere')


    def form_valid(self, form):

        # save in Database
        item = form.save()

        # item.pk stores the saved pk 

        return super().form_valid(form)

    def get_success_url(self)
         # how can i get item.pk from form_valid() here and pass it to another view?

Answer 1

你可以像下面这样做

class SomeView(FormView):
    form_class = SomeForm
    template_name = 'appname/form.html'    

    def form_valid(self, form):
        item = form.save()
        self.pk = item.pk
        return super(SomeView, self).form_valid(form)

    def get_success_url(self):
         #print(self.pk)
         return reverse('some_url', kwargs={'pk': self.pk})

Answer 2

您可以从对象属性访问 pk，如下所示：

class SomeView(CreateView):
    """
    """

    model = Model    
    
    def get_success_url(self) -> str:
        return reverse_lazy('success', kwargs={'pk': self.object.pk})