node_modules/rxjs/Rx 没有导出成员“合并”

Question

我的组件：

import {Observable, Subject , merge} from 'rxjs';
import {debounceTime, distinctUntilChanged, filter, map} from 'rxjs/operators';

focus$ = new Subject<string>();
click$ = new Subject<string>();

search = (text$: Observable<string>) => {
        const debouncedText$ = text$.pipe(debounceTime(200), distinctUntilChanged());
        const clicksWithClosedPopup$ = this.click$.pipe(filter(() => !this.instance.isPopupOpen()));
        const inputFocus$ = this.focus$;

        return merge(debouncedText$, inputFocus$, clicksWithClosedPopup$).pipe(
            map(term => (term === '' ? states
                : states.filter(v => v.toLowerCase().indexOf(term.toLowerCase()) > -1)).slice(0, 10))
        );
}

版本：

"rxjs": "^5.5.6",
"@angular/cli": "1.3.2",
"@angular/compiler-cli": "^4.2.4"

我收到错误：

node_modules/rxjs/Rx"' 没有导出成员“合并”

Answer 1

merge可以用作 orstatic方法instance。

供static方法使用
import { merge } from 'rxjs/observable/merge';

 return merge(debouncedText$, inputFocus$, clicksWithClosedPopup$).pipe(
            map(term => (term === '' ? states
                : states.filter(v => v.toLowerCase().indexOf(term.toLowerCase()) > -1)).slice(0, 10))
        );

供instance方法使用
import { merge } from 'rxjs/operators';

return Observable.merge(debouncedText$, inputFocus$, clicksWithClosedPopup$).pipe(
            map(term => (term === '' ? states
                : states.filter(v => v.toLowerCase().indexOf(term.toLowerCase()) > -1)).slice(0, 10))
        );

Live Demo