了解界面内部界面(嵌入式界面)

Question

我试图用以下代码理解接口嵌入.

我有以下内容:

type MyprojectV1alpha1Interface interface {
    RESTClient() rest.Interface
    SamplesGetter
}

// SamplesGetter has a method to return a SampleInterface.
// A group's client should implement this interface.
type SamplesGetter interface {
    Samples(namespace string) SampleInterface
}

// SampleInterface has methods to work with Sample resources.
type SampleInterface interface {
    Create(*v1alpha1.Sample) (*v1alpha1.Sample, error)
    Update(*v1alpha1.Sample) (*v1alpha1.Sample, error)
    Delete(name string, options *v1.DeleteOptions) error
    DeleteCollection(options *v1.DeleteOptions, listOptions v1.ListOptions) error
    Get(name string, options v1.GetOptions) (*v1alpha1.Sample, error)
    List(opts v1.ListOptions) (*v1alpha1.SampleList, error)
    Watch(opts v1.ListOptions) (watch.Interface, error)
    Patch(name string, pt types.PatchType, data []byte, subresources ...string) (result *v1alpha1.Sample, err error)
    SampleExpansion
}

现在,如果我有以下内容:

func returninterface() MyprojectV1alpha1Interface {
//does something and returns me MyprojectV1alpha1Interface
}
temp := returninterface()

现在,从MyprojectV1alpha1Interface如果我想调用

创建SampleInterface的功能

我需要做什么？

另外,请解释一下这个界面在Golang中是如何工作的.

Answer 1

在这个定义中:

type MyprojectV1alpha1Interface interface {
    RESTClient() rest.Interface
    SamplesGetter
}

你MyprojectV1alpha1Interface嵌入了SamplesGetter界面.

在另一个接口中嵌入接口意味着SamplesGetter可以通过嵌入接口(MyprojectV1alpha1Interface)调用嵌入式接口()的所有方法.

这意味着您可以SamplesGetter在任何实现的对象上调用任何方法MyprojectV1alpha1Interface.

因此,一旦你MyprojectV1alpha1Interface在temp变量中得到一个对象,就可以调用该Samples方法(使用合适的namespace,我无法从您发布的代码中猜出):

sampleInt := temp.Samples("namespace here")

sampleInt然后会有一个SampleInterface对象,因此您可以Create使用您的sampleInt变量调用该函数:

sample, err := sampleInt.Create(<you should use a *v1alpha1.Sample here>)

有关接口如何工作的更多详细信息,我建议您转到官方规范和示例:

https://golang.org/ref/spec#Interface_types

https://gobyexample.com/interfaces