如何捕获Observable.forkJoin(...)中的错误？

Question

两个http调用完成后,我使用Observable.forkJoin()来处理响应,但如果其中任何一个返回错误,我怎么能捕获该错误？

Observable.forkJoin(
  this.http.post<any[]>(URL, jsonBody1, postJson) .map((res) => res),
  this.http.post<any[]>(URL, jsonBody2, postJson) .map((res) => res)
)
.subscribe(res => this.handleResponse(res))

Answer 1

您可能会catch传递到每个可观察对象中的错误forkJoin:

// Imports that support chaining of operators in older versions of RxJS
import {Observable} from 'rxjs/Observable';
import {forkJoin} from 'rxjs/add/observable/forkJoin';
import {of} from 'rxjs/add/observable/of';
import {map} from 'rxjs/add/operator/map';
import {catch} from 'rxjs/add/operator/catch';

// Code with chaining operators in older versions of RxJS
Observable.forkJoin(
  this.http.post<any[]>(URL, jsonBody1, postJson) .map((res) => res)).catch(e => Observable.of('Oops!')),
  this.http.post<any[]>(URL, jsonBody2, postJson) .map((res) => res)).catch(e => Observable.of('Oops!'))
)
.subscribe(res => this.handleResponse(res))

还要注意的是,如果你使用RxJS6,你需要使用catchError的,而不是catch和pipe运营商,而不是链接.

// Imports in RxJS6
import {forkJoin, of} from 'rxjs';
import {map, catchError} from 'rxjs/operators';

// Code with pipeable operators in RxJS6
forkJoin(
  this.http.post<any[]>(URL, jsonBody1, postJson) .pipe(map((res) => res), catchError(e => of('Oops!'))),
  this.http.post<any[]>(URL, jsonBody2, postJson) .pipe(map((res) => res), catchError(e => of('Oops!')))
)
  .subscribe(res => this.handleResponse(res))

Answer 2

这对我有用：

forkJoin(
 this.http.post<any[]>(URL, jsonBody1, postJson).pipe(catchError(error => of(error))),
 this.http.post<any[]>(URL, jsonBody2, postJson)
)
.subscribe(res => this.handleResponse(res))

第二次 HTTP 调用会正常调用，即使第一次调用出错