srb*_*ert 27 ruby activerecord arel
使用ruby和新的Activerecord在列中查找具有重复值的记录的最佳方法是什么?
fl0*_*00r 50
将@TuteC翻译成ActiveRecord:
sql = 'SELECT id,
COUNT(id) as quantity
FROM types
GROUP BY name
HAVING quantity > 1'
#=>
Type.select("id, count(id) as quantity")
.group(:name)
.having("quantity > 1")
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bro*_*okr 24
以下是我使用AREL帮助程序解决它的方法,而且没有自定义SQL:
Person.select("COUNT(last_name) as total, last_name")
.group(:last_name)
.having("COUNT(last_name) > 1")
.order(:last_name)
.map{|p| {p.last_name => p.total} }
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真的,这只是编写SQL的一种更好的方法.这将查找具有重复last_name值的所有记录,并告诉您在一个漂亮的哈希中有多少以及姓氏是多少.
Sam*_*Sam 16
我用2016年的堆栈(Rails 4.2,Ruby 2.2)击败了这个问题,并得到了我想要的东西:
> Model.select([:thing]).group(:thing).having("count(thing) > 1").all.size
=> {"name1"=>5, "name2"=>4, "name3"=>3, "name4"=>2, "name5"=>2}
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Tut*_*teC 11
使用自定义SQL,它会找到types相同的值name:
sql = 'SELECT id, COUNT(id) as quantity FROM types
GROUP BY name HAVING quantity > 1'
repeated = ActiveRecord::Base.connection.execute(sql)
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在Rails 2.x中,select是AR类的私有方法.只需使用find():
klass.find(:all,
:select => "id, count(the_col) as num",
:conditions => ["extra conditions here"],
:group => 'the_col',
:having => "num > 1")
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