Can*_*ice 4 javascript group-by
我努力找到我在其他stackoverflow帖子中寻找的解决方案,尽管我强烈地觉得它必须存在.如果确实如此,请向我转发正确的方向.
我试图通过javascript使用体育数据做一个非常标准的组.我有以下对象数组:
const myData = [
{team: "GSW", pts: 120, ast: 18, reb: 11},
{team: "GSW", pts: 125, ast: 28, reb: 18},
{team: "GSW", pts: 110, ast: 35, reb: 47},
{team: "HOU", pts: 100, ast: 17, reb: 43},
{team: "HOU", pts: 102, ast: 14, reb: 32},
{team: "SAS", pts: 127, ast: 21, reb: 25},
{team: "SAS", pts: 135, ast: 25, reb: 37},
{team: "SAS", pts: 142, ast: 18, reb: 27}
]
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我的数据中的每一行都对应于特定篮球比赛的结果.简单地说,我想按数据分组,并将均值/平均函数应用于分组数据.我期望的结果是:
const groupedData = [
{team: "GSW", pts: 118.3, ast: 27.0, reb: 25.3},
{team: "HOU", pts: 101, ast: 15.5, reb: 37.5},
{team: "SAS", pts: 134.7, ast: 21.3, reb: 29.7}
]
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我更喜欢在这里使用带有reduce()的vanilla javascript ...鉴于我对reduce的了解,它似乎是最好的方法.我目前正在研究这个问题,并且如果我能在别人发布答案之前让它上班,我会发布.
编辑:我的实际数据有~30个键.我希望找到一个解决方案,简单地要求我(a)仅指定要分组的团队列,并假设它将其余列分组,或者(b)传递一组stat列(pts,asts等).而不是为每个统计数据创建一条线.
谢谢!
一种方法是使用reduce
和map
结合使用.
const myData = [
{team: "GSW", pts: 120, ast: 18, reb: 11},
{team: "GSW", pts: 125, ast: 28, reb: 18},
{team: "GSW", pts: 110, ast: 35, reb: 47},
{team: "HOU", pts: 100, ast: 17, reb: 43},
{team: "HOU", pts: 102, ast: 14, reb: 32},
{team: "SAS", pts: 127, ast: 21, reb: 25},
{team: "SAS", pts: 135, ast: 25, reb: 37},
{team: "SAS", pts: 142, ast: 18, reb: 27}
]
// Calculate the sums and group data (while tracking count)
const reduced = myData.reduce(function(m, d){
if(!m[d.team]){
m[d.team] = {...d, count: 1};
return m;
}
m[d.team].pts += d.pts;
m[d.team].ast += d.ast;
m[d.team].reb += d.reb;
m[d.team].count += 1;
return m;
},{});
// Create new array from grouped data and compute the average
const result = Object.keys(reduced).map(function(k){
const item = reduced[k];
return {
team: item.team,
ast: item.ast/item.count,
pts: item.pts/item.count,
reb: item.reb/item.count
}
})
console.log(JSON.stringify(result,null,4));
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编辑:刚看到你对这个问题的更新.如果您可以将白名单(提供要计算的密钥数组)或黑名单(提供要忽略的密钥数组)密钥以编程方式执行,则可以取消每个密钥的每一行.
const myData = [
{team: "GSW", pts: 120, ast: 18, reb: 11},
{team: "GSW", pts: 125, ast: 28, reb: 18},
{team: "GSW", pts: 110, ast: 35, reb: 47},
{team: "HOU", pts: 100, ast: 17, reb: 43},
{team: "HOU", pts: 102, ast: 14, reb: 32},
{team: "SAS", pts: 127, ast: 21, reb: 25},
{team: "SAS", pts: 135, ast: 25, reb: 37},
{team: "SAS", pts: 142, ast: 18, reb: 27}
]
/**
* Function which accepts a data array and a list of whitelisted
* keys to find the average of each key after grouping
*/
function getGroupedData(data, whitelist) {
// Calculate the sums and group data (while tracking count)
const reduced = data.reduce(function(m, d) {
if (!m[d.team]) {
m[d.team] = { ...d,
count: 1
};
return m;
}
whitelist.forEach(function(key) {
m[d.team][key] += d[key];
});
m[d.team].count += 1;
return m;
}, {});
// Create new array from grouped data and compute the average
return Object.keys(reduced).map(function(k) {
const item = reduced[k];
const itemAverage = whitelist.reduce(function(m, key) {
m[key] = item[key] / item.count;
return m;
}, {})
return {
...item, // Preserve any non white-listed keys
...itemAverage // Add computed averege for whitelisted keys
}
})
}
console.log(JSON.stringify(getGroupedData(myData, ['pts', 'ast', 'reb']), null, 4));
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