我是graphql的新手。我正在尝试实现自定义标量类型“电子邮件”。但低于错误。请你帮助我好吗?
作者:com.coxautodev.graphql.tools.SchemaClassScannerError:需要一个名为“Email”的用户定义的 GraphQL 标量类型,但没有找到!在 com.coxautodev.graphql.tools.SchemaClassScanner.validateAndCreateResult(SchemaClassScanner.kt:144) ~[graphql-java-tools-4.3.0.jar:na] 在 com.coxautodev.graphql.tools.SchemaClassScanner.scanForClasses(SchemaClassScanner. kt:94) ~[graphql-java-tools-4.3.0.jar:na]
配置:
scalar Email
type Greeting {
id: ID!
message: String!
email:Email
}
type Query {
getGreeting(id: ID!): Greeting
}
type Mutation {
newGreeting(message: String!): Greeting!
}
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版本信息:
springBootVersion = '1.5.8.RELEASE'
com.graphql-java:graphql-java:6.0')
com.graphql-java:graphql-java-tools:4.3.0')
com.graphql-java:graphql-java-servlet:4.7.0')
org.springframework.boot:spring-boot-starter-web')
com.graphql-java:graphql-spring-boot-starter:3.10.0')
com.graphql-java:graphiql-spring-boot-starter:3.10.0')
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请帮忙...
小智 2
尝试这个:
@Component
public class ScalarEMail extends GraphQLScalarType {
public ScalarEMail() {
super("Email", "Scalar Email", new Coercing() {
@Override
public Object serialize(Object o) throws CoercingSerializeException {
return ((Email) o).getEmail();
}
@Override
public Object parseValue(Object o) throws CoercingParseValueException {
return serialize(o);
}
@Override
public Object parseLiteral(Object o) throws CoercingParseLiteralException {
return Email.valueOf(((StringValue) o).getValue());
}
});
}
}
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