如何在 Graphql-java 中实现自定义标量?

KiY*_*iYo 5 graphql

我是graphql的新手。我正在尝试实现自定义标量类型“电子邮件”。但低于错误。请你帮助我好吗?

作者:com.coxautodev.graphql.tools.SchemaClassScannerError:需要一个名为“Email”的用户定义的 GraphQL 标量类型,但没有找到!在 com.coxautodev.graphql.tools.SchemaClassScanner.validateAndCreateResult(SchemaClassScanner.kt:144) ~[graphql-java-tools-4.3.0.jar:na] 在 com.coxautodev.graphql.tools.SchemaClassScanner.scanForClasses(SchemaClassScanner. kt:94) ~[graphql-java-tools-4.3.0.jar:na]

配置:

scalar Email

type Greeting {
  id: ID!
  message: String!
  email:Email
}

type Query {
  getGreeting(id: ID!): Greeting
}

type Mutation {
  newGreeting(message: String!): Greeting!
}
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版本信息:

springBootVersion = '1.5.8.RELEASE'

com.graphql-java:graphql-java:6.0')

com.graphql-java:graphql-java-tools:4.3.0')

com.graphql-java:graphql-java-servlet:4.7.0')

org.springframework.boot:spring-boot-starter-web')

com.graphql-java:graphql-spring-boot-starter:3.10.0')

com.graphql-java:graphiql-spring-boot-starter:3.10.0')      
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请帮忙...

小智 2

尝试这个:

@Component
public class ScalarEMail extends GraphQLScalarType {
    public ScalarEMail() {
        super("Email", "Scalar Email", new Coercing() {
            @Override
            public Object serialize(Object o) throws CoercingSerializeException {
                return ((Email) o).getEmail();
            }

            @Override
            public Object parseValue(Object o) throws CoercingParseValueException {
                return serialize(o);
            }

            @Override
            public Object parseLiteral(Object o) throws CoercingParseLiteralException {
                return Email.valueOf(((StringValue) o).getValue());
            }
        });
    }
}
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