在 Oracle 中,如何验证对象类型层次结构中使用的对象类型?

Siq*_*ira 3 oop oracle types plsql oracle12c

我在 Oracle 模式中有一个类型层次结构:

CREATE OR REPLACE TYPE FV AS OBJECT (
   idno           NUMBER)
NOT FINAL;
/

CREATE TYPE FV_Integer UNDER FV (
   features INTEGER_ARRAY)
   NOT FINAL;
/


CREATE TYPE FV_Number UNDER FV (
   features NUMBER_ARRAY)
   NOT FINAL;
/
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我想构建一个 PLSQL 函数来验证哪种类型的层次结构是对象:对于函数虚拟(obj1 FV,obj2 FV)...我如何检查用户正在使用的层次结构的对象类型是什么?

例如,我想打印对象类型名称(该函数用于说明,它不是真正的 pl/sql 代码):

 dummy(obj1 FV, obj2 FV){
      if obj1%type = FV_INTEGER
          THEN print 'FV_INTEGER'
      endif
      if obj2%type = FV_NUMBER
          THEN print 'FV_NUMBER'
      endif
}
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Wil*_*son 5

您可以使用以下命令检查对象的类型sys.anydata

create or replace function which_type
    ( p_fv fv )
    return varchar2
as
begin
    return sys.anydata.gettypename(sys.anydata.convertobject(p_fv));
end which_type;
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测试:

create or replace type number_array as table of number;
create or replace type integer_array as table of integer;

create or replace type fv as object (
   idno           number)
not final;
/

create type fv_integer under fv (
   features integer_array)
   not final;
/

create type fv_number under fv (
   features number_array)
   not final;
/

create table fv_test (my_fv fv);

insert into fv_test values (fv(1));
insert into fv_test values (fv_integer(1, integer_array(1)));
insert into fv_test values (fv_number(1, number_array(1)));

select which_type(my_fv) from fv_test;

WHICH_TYPE(MY_FV)
-------------------------
WILLIAM.FV
WILLIAM.FV_INTEGER
WILLIAM.FV_NUMBER

3 rows selected.
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