Ser*_*kov 6 oracle uuid jdbc dbsetup
我在Oracle中有RAW(16)PK列,并尝试使用JDBC插入其中:
PreparedStatement stmt = connection.prepareStatement("insert into COUNTRY (id, state, version, code, name, nationality, issuing_entity, country) values (?, ?, ?, ?, ?, ?, ?, ?)");
UUID id = UUID.randomUUID();
stmt.setObject(1, id, Types.BINARY);
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但是,我得到一个例外:
java.sql.SQLException: Invalid column type
at oracle.jdbc.driver.OraclePreparedStatement.setObjectCritical(OraclePreparedStatement.java:8494)
at oracle.jdbc.driver.OraclePreparedStatement.setObjectInternal(OraclePreparedStatement.java:7995)
at oracle.jdbc.driver.OraclePreparedStatement.setObject(OraclePreparedStatement.java:8559)
at oracle.jdbc.driver.OraclePreparedStatementWrapper.setObject(OraclePreparedStatementWrapper.java:225)
at com.zaxxer.hikari.pool.HikariProxyPreparedStatement.setObject(HikariProxyPreparedStatement.java)
at rw.gov.dgie.framework.test.AbstractTestCaseWithDB.tryToInsertCountry(AbstractTestCaseWithDB.java:78)
at rw.gov.dgie.framework.test.AbstractTestCaseWithDB.dbSetup(AbstractTestCaseWithDB.java:62)
at test.rw.gov.dgie.bms.terr.service.TestCountryService.init(TestCountryService.java:37)
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尝试使用DbSetup插入测试数据时,我遇到了相同的异常。
有没有办法使JDBC将UUID插入RAW(16)列?
我正在使用Oracle JDBC 12.2.0.1.0。
您必须将UUID转换为字节数组。请参见asBytes方法。
之后,绑定就像使用一样简单setBytes。
例
def stmt = con.prepareStatement("insert into TAB_UUID (id, uuid) values (?,?)")
// bind
stmt.setInt(1,1)
def uuid = UUID.randomUUID()
stmt.setBytes(2,asBytes(uuid))
def rowCount = stmt.executeUpdate()
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这里只是为了防止链接不起作用将UUID转换为字节数组的方法
public static byte[] asBytes(UUID uuid) {
ByteBuffer bb = ByteBuffer.wrap(new byte[16]);
bb.putLong(uuid.getMostSignificantBits());
bb.putLong(uuid.getLeastSignificantBits());
return bb.array();
}
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小智 5
Oracle 没有真正的 UUID 数据类型,处理RAW(16)实际上是 PITA。
我们所做的是将 UUID 作为字符串传递给使用以下命令的 SQL 语句hextoraw():
String sql = "insert into foo (id) values (hextoraw(?))";
PreparedStatement pstmt = connection.prepareStatement(sql);
UUID uid = UUID.randomUUID();
pstmt.setString(1, uid.toString().replaceAll("-", ""));
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