我有一个简单的问题,我无法弄清楚.我有一个包含两个因子(distance)和年(years)的数据帧.我想years用0 来完成每个因子的所有值.
即从这个:
distance years area
1 NPR 3 10
2 NPR 4 20
3 NPR 7 30
4 100 1 40
5 100 5 50
6 100 6 60
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得到这个:
distance years area
1 NPR 1 0
2 NPR 2 0
3 NPR 3 10
4 NPR 4 20
5 NPR 5 0
6 NPR 6 0
7 NPR 7 30
8 100 1 40
9 100 2 0
10 100 3 0
11 100 4 0
12 100 5 50
13 100 6 60
14 100 7 0
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我试着申请expand()功能:
library(tidyr)
library(dplyr, warn.conflicts = FALSE)
expand(df, years = 1:7)
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但这只会产生一个列数据帧而不会扩展原始数据帧:
# A tibble: 7 x 1
years
<int>
1 1
2 2
3 3
4 4
5 5
6 6
7 7
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或者expand.grid()两个都不工作:
require(utils)
expand.grid(df, years = 1:7)
Error in match.names(clabs, names(xi)) :
names do not match previous names
In addition: Warning message:
In format.data.frame(x, digits = digits, na.encode = FALSE) :
corrupt data frame: columns will be truncated or padded with NAs
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expand我的数据框有一个简单的方法吗?以及如何根据两个类别进行扩展:distance和uniqueLoc?
distance <- rep(c("NPR", "100"), each = 3)
years <-c(3,4,7, 1,5,6)
area <-seq(10,60,10)
uniqueLoc<-rep(c("a", "b"), 3)
df<-data.frame(uniqueLoc, distance, years, area)
> df
uniqueLoc distance years area
1 a NPR 3 10
2 b NPR 4 20
3 a NPR 7 30
4 b 100 1 40
5 a 100 5 50
6 b 100 6 60
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你可以使用这个tidyr::complete功能:
complete(df, distance, years = full_seq(years, period = 1), fill = list(area = 0))
# A tibble: 14 x 3
distance years area
<fct> <dbl> <dbl>
1 100 1. 40.
2 100 2. 0.
3 100 3. 0.
4 100 4. 0.
5 100 5. 50.
6 100 6. 60.
7 100 7. 0.
8 NPR 1. 0.
9 NPR 2. 0.
10 NPR 3. 10.
11 NPR 4. 20.
12 NPR 5. 0.
13 NPR 6. 0.
14 NPR 7. 30.
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或略短:
complete(df, distance, years = 1:7, fill = list(area = 0))
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