ilM*_*ion 6 interceptor oauth-2.0 typescript angular
我正在使用OAuth2隐式流程开发Angular 5应用程序.
我有服务执行HTTP调用,遵循我的服务示例:
@Injectable()
export class MyService {
constructor(public http: HttpClient) { }
public getAll(): Observable<Persona[]> {
return this.http.get<Persona[]>("http://mywebservice/persone");
}
}
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我正在使用拦截器进行授权并添加自定义属性.跟随我的auth拦截器:
import { HttpEvent, HttpHandler, HttpInterceptor, HttpRequest } from '@angular/common/http';
import { Injectable } from '@angular/core';
import { Observable } from "rxjs";
@Injectable()
export class AuthInterceptor implements HttpInterceptor {
constructor() {
}
intercept(request: HttpRequest<any>, next: HttpHandler): Observable<HttpEvent<any>> {
let accessToken = sessionStorage.getItem("access_token");
if(accessToken)
{
request = request.clone({
setHeaders: {
Authorization: `Bearer ${accessToken}`
}
});
}
return next.handle(request);
}
}
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以及我如何使用我的服务:
public myMethod() {
this.myService.getAll().subscribe(
result => {
console.log(result);
}, error => {
// I don't want add redirection there...
console.error(error);
});
}
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现在我需要的是,当任何HTTP调用接收到401结果时,应用程序会将用户重定向到登录页面.
如何在没有代码重复的情况下获得此结果?
非常感谢
ilM*_*ion 11
我解决了我的问题,改变我的拦截器如下:
@Injectable()
export class AuthInterceptor implements HttpInterceptor {
constructor() {
}
intercept(request: HttpRequest<any>, next: HttpHandler): Observable<HttpEvent<any>> {
let accessToken = sessionStorage.getItem("access_token");
if(accessToken)
{
request = request.clone({
setHeaders: {
Authorization: `Bearer ${accessToken}`
}
});
}
return next.handle(request).do((event: HttpEvent<any>) => {
if (event instanceof HttpResponse) {
}
}, (err: any) => {
if (err instanceof HttpErrorResponse) {
if (err.status === 401) {
this.router.navigate(['login']);
}
}
});
}
}
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我在那里找到了解决方案:https://medium.com/@ryanchenkie_40935/angular-authentication-using-the-http-client-and-http-interceptors-2f9d1540eb8
Jal*_*ini 10
仅为了支持新读者,请注意,在angular 7中,应使用pipe()而不是do()或catch():
return next.handle(request).pipe(catchError(err => {
if (err.status === 401) {
MyComponent.logout();
}
const error = err.error.message || err.statusText;
return throwError(error);
}));
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