如何编写批处理文件以返回 WMIC 结果

Question

How do I write a batch file to return true if the manufacturer of the motherboard is ASUSTek COMPUTER INC. and return false if it's not using the wmic command?

The command is as below:

wmic baseboard get Manufacturer

and it returns:

Manufacturer
ASUSTeK COMPUTER INC.

and I only need to compare the string ASUSTeK COMPUTER INC..

Answer 1

要捕获命令的输出，wmic请使用for /F：

set "BOARD="
for /F "skip=1 delims=" %%I in ('
    wmic BaseBoard get Manufacturer
') do (
    for /F "delims=" %%J in ("%%I") do (
        set "BOARD=%%J"
    )
)
rem // Compare retrieved string:
if /I "%BOARD%"=="ASUSTeK COMPUTER INC." (
    echo True
) else (
    echo False
)

for /F为了正确转换 Unicode 输出，需要两个嵌套循环wmic。

但是，您也可以wmic直接过滤输出，如下所示：

wmic BaseBoard where "Manufacturer='ASUSTeK COMPUTER INC.'" get Manufacturer 2>&1 > nul | find /V "" > nul && (echo False) || (echo True)

该where子句进行过滤；如果未找到匹配项，则在STD_ERRNo Instance(s) Available.流上返回（句柄）。该表达式抑制STD_OUT流（handle ）并将STD_ERR重定向到STD_OUT，因此将接收它；当流不为空时，搜索表达式会找到匹配项。如果找到匹配则返回退出代码，否则返回；运算符并检查退出代码并有条件地执行相应的命令。22>&1 > nul1 find/V ""find01 &&||echo