Pot*_*mpo 1 haskell types casting complex-numbers
似乎提高Complex Int权力违反了某些合同.我错了吗?
以下最小例子
compl :: Complex Int -> Maybe (Complex Int)
compl d = (d^) <$> Just 3
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并且错误消息:
No instance for (RealFloat Int) arising from an operator section
In the first argument of ‘(<$>)’, namely ‘(d ^)’
In the expression: (d ^) <$> Just 3
In an equation for ‘compl’: compl d = (d ^) <$> Just 3
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有没有办法解决?允许这种类型是浮点数在我的程序中没有任何意义.
(^)是一种方法Num. 该Complex类型的实例Num声明为:
instance RealFloat a => Num (Complex a)
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也就是说,除非是a ,否则你不能将a Complex a视为a .使用等代替.NumaRealFloatIntComplex Double
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