PIL:使图像按百分比透明

pau*_*aul 3 python python-imaging-library

如何使watermark图像透明?例如,60% 透明。我已经尝试过,putalpha但似乎没有按预期工作

from PIL import Image


temp_image = Image.open('test1.jpg')
watermark = Image.open('watermark.png')

x, y = temp_image.size

image_with_watermark = Image.new('RGBA', (x, y), (0, 0, 0, 0))
image_with_watermark.paste(temp_image, (0, 0))
image_with_watermark.paste(watermark, (0, 0), mask=watermark)
image_with_watermark.show()
Run Code Online (Sandbox Code Playgroud)

编辑:

好的,这有效,需要弄清楚如何使用 % 进行设置

from PIL import Image


temp_image = Image.open('test1.jpg')
watermark = Image.open('watermark.png')

x, y = temp_image.size

watermask = watermark.convert("L").point(lambda x: min(x, 50))
watermark.putalpha(watermask)

image_with_watermark = Image.new('RGBA', (x, y), (0, 0, 0, 0))
image_with_watermark.paste(temp_image, (0, 0))
image_with_watermark.paste(watermark, (0, 0), mask=watermark)
image_with_watermark.show()
Run Code Online (Sandbox Code Playgroud)

嗯,水印的质量非常低:

watermask = watermark.convert("L").point(lambda x: min(x, 50))
watermark.putalpha(watermask)
Run Code Online (Sandbox Code Playgroud)

实现我所需要的最佳方法是什么?

And*_*kha 5

这是一个适用于 RGB 和 RGBA 水印图像的解决方案:

from PIL import Image

TRANSPARENCY = 65       # percentage

temp_image = Image.open('test1.jpg')
watermark = Image.open('watermark.png')    

if watermark.mode!='RGBA':
    alpha = Image.new('L', watermark.size, 255)
    watermark.putalpha(alpha)

paste_mask = watermark.split()[3].point(lambda i: i * TRANSPARENCY / 100.)
temp_image.paste(watermark, (0,0), mask=paste_mask)
temp_image.save('res.png')
Run Code Online (Sandbox Code Playgroud)

示例图像(作者 - Neil Howard):

新加坡

示例水印(背景透明):

堆栈溢出标题

示例结果:

新加坡 + Stack Overflow 水印