use*_*487 6 android xamarin.android xamarin
我正在使用 Xamarin for Android 并且我在 AlertDialog.Builder.Show() 方法中收到此错误,但它只发生在一些三星(使用 Android 7.0)设备上,我们尝试了一些其他设备,但这个问题没有不会发生。我只是在使用应用程序一段时间后才得到它。堆栈跟踪如下
at System.Runtime.ExceptionServices.ExceptionDispatchInfo.Throw () [0x0000c] in <f32579baafc1404fa37ba3ec1abdc0bd>:0
at Java.Interop.JniEnvironment+InstanceMethods.CallObjectMethod (Java.Interop.JniObjectReference instance, Java.Interop.JniMethodInfo method, Java.Interop.JniArgumentValue* args) [0x00069] in <7802aa64ad574c33adca332a3fa9706a>:0
at Java.Interop.JniPeerMembers+JniInstanceMethods.InvokeVirtualObjectMethod (System.String encodedMember, Java.Interop.IJavaPeerable self, Java.Interop.JniArgumentValue* parameters) [0x0002a] in <7802aa64ad574c33adca332a3fa9706a>:0
at Android.App.AlertDialog+Builder.Show () [0x0000a] in <dc51acef1f304f0dab449a7fc6039799>:0
at Prizma.Controls.Common.BindingComboBox.ShowDialog () [0x00062] in C:\TeamProjects\PrizmaProject\Main\MobileSales.iOS\Prizma.Controls.iOS\Common\BindingComboBox.cs:408
--- End of managed Android.Views.WindowManagerBadTokenException stack trace ---
android.view.WindowManager$BadTokenException: Unable to add window -- window android.view.ViewRootImpl$W@cb70704 has already been added
at android.view.ViewRootImpl.setView(ViewRootImpl.java:902)
at android.view.WindowManagerGlobal.addView(WindowManagerGlobal.java:377)
at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:97)
at android.app.Dialog.show(Dialog.java:404)
at android.app.AlertDialog$Builder.show(AlertDialog.java:1136)
at mono.android.view.View_OnClickListenerImplementor.n_onClick(Native Method)
at mono.android.view.View_OnClickListenerImplementor.onClick(View_OnClickListenerImplementor.java:30)
at android.view.View.performClick(View.java:6261)
at android.widget.TextView.performClick(TextView.java:11185)
at android.view.View$PerformClick.run(View.java:23752)
at android.os.Handler.handleCallback(Handler.java:751)
at android.os.Handler.dispatchMessage(Handler.java:95)
at android.os.Looper.loop(Looper.java:154)
at android.app.ActivityThread.main(ActivityThread.java:6776)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1518)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1408)
Run Code Online (Sandbox Code Playgroud)
我的代码是这样的
try
{
AlertDialog.Builder a = new AlertDialog.Builder(MainActivity);
a.SetTitle("Select");
a.SetAdapter(_Adapter, new EventHandler<DialogClickEventArgs>(ClosedDialog));
a.Create();
a.Show();
}
catch (Exception ex)
{
//Exception code
}
Run Code Online (Sandbox Code Playgroud)
我将 AlertDialog.Builder Show() 方法放在 Try Catch 中,但是在我第一次得到异常之后,我每次都得到它。
一些备注
请帮助我,我有数周的时间来解决这个问题,而我的拥有三星设备的客户正在杀死我:)
提前致谢。
问候
艾伦
在片段中显示您的对话框,如下所示: use if (!IsFinishing) in an activity
if (!((Activity)Context).IsFinishing)
{
try
{
AlertDialog.Builder a = new AlertDialog.Builder(MainActivity);
a.SetTitle("Select");
a.SetAdapter(_Adapter, new EventHandler<DialogClickEventArgs>(ClosedDialog));
a.Create();
a.Show();
}
catch (Exception ex)
{
//Exception code
}
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
4077 次 |
| 最近记录: |