警告:指针和整数以及转义字符之间的比较

Question

1)我在https://www.tutorialspoint.com/compile_c_online.php上测试了我的代码 它以某种方式通过显示1,3,27,23,19的理想输出工作,但也给我错误消息,这很奇怪,因为所有我的函数没有任何整数.任何人都可以告诉我为什么显示错误的行是错误的？

2)我怀疑它与'未正确处理的角色有关,但我不知道如何打印除%%和之外的所有特殊字符\\.有人可以指引我查看完整列表吗？

编辑:我意识到实际上有2个转义字符我错了(在https://www.geeksforgeeks.org/escape-sequences-c/上找到了正确的术语),这是单引号和双引号.除了这个清单之外还有什么吗？

#include <stdio.h>

int improvedCountWords(const char *str) {

    int size=0;
    int number=0;
    int length=0;
    while (str[size]!='\0'){
        if (str[size]==' ' || str[size]=='.' || str[size]=='\\' || str[size]=='*' || str[size]=='"'){
            if (length>0){
                number+=1;
                length=0;
            }

        }
        else if (str[size]=='-' || str[size]=="'"){
            if (length>0){
                length++;
            }

        }
        else{
            length++;
        }
        size++;
    }
    if (length>0){
        number++;
    }
    return number;
}


int main(){
    char s1[]="Panting heavily, he continues his exercises -- grepping, installing new packages, logging in as root, and writing replacements for two-year-old shell scripts in Python.";

    char s2[]="\" You'll know why Python is better than Perl... when you try to read your code *six* months from now ...\"";
    char s3[]="With Yoda strapped to his back, Luke climbs up one of the many thick vines that grow in the swamp until he reaches the Dagobah statistics lab.";

    int x1=improvedCountWords("Python");        
    int x2=improvedCountWords("Python is AWESOME");
    int x3=improvedCountWords(s3);
    int x4=improvedCountWords(s1);
    int x5=improvedCountWords(s2);


    printf("%d,%d,%d,%d,%d",x1,x2,x3,x4,x5);



    return 0;
}

Answer 1

你的指针是"'",而int是比较str[size]中提升的字符值==.这是在这一行,它没有得到妥善处理;

    else if (str[size]=='-' || str[size]=="'"){

你可能需要将它与'\''这样比较;

    else if (str[size]=='-' || str[size]=='\''){