use*_*987 5 django django-rest-framework django-channels django-rest-framework-jwt
我正在尝试为 django 频道设置一个身份验证中间件。我希望这个中间件只对 websocket 请求有效。
在这种情况下,我似乎没有获得完整的中间件功能。例如,我无法response = self.get_response(scope)工作:
'TokenAuthMiddleware' object has no attribute 'get_response'
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现在这个中间件一切都很好(它只为 websocket 请求激活,而不是在 中注册settings.py),除了我需要一种方法来修改响应状态代码(阻止匿名用户并设置错误代码ExpiredSignatureError)。任何帮助表示赞赏。我使用 Django2.0.6和 channels 2.1.1。jwt 认证通过djangorestframework-jwt
中间件:
import jwt, re
import traceback
import logging
from channels.auth import AuthMiddlewareStack
from django.contrib.auth.models import AnonymousUser
from django.conf import LazySettings
from jwt import InvalidSignatureError, ExpiredSignatureError, DecodeError
from project.models import MyUser
settings = LazySettings()
logger = logging.getLogger(__name__)
class TokenAuthMiddleware:
"""
Token authorization middleware for Django Channels 2
"""
def __init__(self, inner):
self.inner = inner
def __call__(self, scope):
headers = dict(scope['headers'])
auth_header = None
if b'authorization' in headers:
auth_header = headers[b'authorization'].decode()
else:
try:
auth_header = _str_to_dict(headers[b'cookie'].decode())['X-Authorization']
except:
pass
logger.info(auth_header)
if auth_header:
try:
user_jwt = jwt.decode(
auth_header,
settings.SECRET_KEY,
)
scope['user'] = MyUser.objects.get(
id=user_jwt['user_id']
)
except (InvalidSignatureError, KeyError, ExpiredSignatureError, DecodeError):
traceback.print_exc()
pass
except Exception as e: # NoQA
logger.error(scope)
traceback.print_exc()
return self.inner(scope)
TokenAuthMiddlewareStack = lambda inner: TokenAuthMiddleware(AuthMiddlewareStack(inner))
def _str_to_dict(str):
return {k: v.strip('"') for k, v in re.findall(r'(\S+)=(".*?"|\S+)', str)}
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路由.py
application = ProtocolTypeRouter({
# (http->django views is added by default)
'websocket': TokenAuthMiddlewareStack(
URLRouter(
cmonitorserv.routing.websocket_urlpatterns
)
),
})
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无法找到使用中间件的解决方案。现在通过处理身份验证权限来解决consumers.py
def _is_authenticated(self):
if hasattr(self.scope, 'auth_error'):
return False
if not self.scope['user'] or self.scope['user'] is AnonymousUser:
return False
return True
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另一件重要的事情似乎没有在任何地方记录 - 要拒绝与自定义错误代码的连接,我们需要首先接受它。
class WebConsumer(WebsocketConsumer):
def connect(self):
self.accept()
if self._is_authenticated():
....
else:
logger.error("ws client auth error")
self.close(code=4003)
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