Shi*_*mar 19
这是一种方法.
您以NameValueCollection的形式发送此方法url和name/value参数.该方法在端点上生成Http Post并将响应作为字符串返回.
当然,取决于你正在做什么/为什么这样做以及这个方法被调用多少次,可能还有其他选择.但是在您提供有关您的特定需求的更多信息之前,这种方法已经足够了.
下面的方法使用任务(.NET 4.0)和异步方法,因此如果您在循环中进行多次调用,它将比下一个代码列表更快.
static string GetWebResponse(string url, NameValueCollection parameters)
{
var httpWebRequest = (HttpWebRequest)WebRequest.Create(url);
httpWebRequest.ContentType = "application/x-www-form-urlencoded";
httpWebRequest.Method = "POST";
var sb = new StringBuilder();
foreach (var key in parameters.AllKeys)
sb.Append(key + "=" + parameters[key] + "&");
sb.Length = sb.Length - 1;
byte[] requestBytes = Encoding.UTF8.GetBytes(sb.ToString());
httpWebRequest.ContentLength = requestBytes.Length;
using (var requestStream = httpWebRequest.GetRequestStream())
{
requestStream.Write(requestBytes, 0, requestBytes.Length);
requestStream.Close();
}
Task<WebResponse> responseTask = Task.Factory.FromAsync<WebResponse>(httpWebRequest.BeginGetResponse, httpWebRequest.EndGetResponse, null);
using (var responseStream = responseTask.Result.GetResponseStream())
{
var reader = new StreamReader(responseStream);
return reader.ReadToEnd();
}
}
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你也可以使用WebClient(它有点简单).此方法将post参数作为表单中的字符串
name1=value1&name2=value2&name3=value3
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因此,如果您使用此方法,请确保传递您的参数或修改实现,就像上面的代码.
static string HttpPost(string url, string Parameters)
{
var req = System.Net.WebRequest.Create(url);
req.ContentType = "application/x-www-form-urlencoded";
req.Method = "POST";
byte[] bytes = System.Text.Encoding.ASCII.GetBytes(Parameters);
req.ContentLength = bytes.Length;
System.IO.Stream os = req.GetRequestStream ();
os.Write (bytes, 0, bytes.Length);
os.Close ();
System.Net.WebResponse resp = req.GetResponse();
if (resp== null)
return null;
var sr = new StreamReader(resp.GetResponseStream());
return sr.ReadToEnd().Trim();
}
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