swift4:未批准此客户端应用程序的回调URL

Question

我正在使用swift4:我想通过Twitter登录应用程序,但是当我按下twitter按钮登录时出现此错误:

未批准此客户端应用程序的回调URL.可以在您的应用程序设置中调整已批准的回调URL"UserInfo = {NSLocalizedDescription =未批准此客户端应用程序的回调URL.可在您的应用程序设置中调整已批准的回调URL}错误:可选("请求失败:禁止(403)")

我按照这个文档并设置了所有plist变量和app delegate,这是我登录页面中的代码:

@IBAction func loginWithTwitter(_ sender: Any) {

    TWTRTwitter.sharedInstance().logIn(completion: {
        (session, error) in
        if let sess = session {
            print("session: ",sess.authToken, sess.authTokenSecret, sess.userID, sess.userName)
            self.loginWithTwitter(twitter_id: sess.userID, name: sess.userName)
        } else {
            print("error: ", error?.localizedDescription as Any)
        }
    })
}

func loginWithTwitter(twitter_id: String, name: String) {
    self.deviceMac = UIDevice.current.identifierForVendor!.uuidString
    KRProgressHUD.show(withMessage: "????? ....")
    API.loginWithTwitter(mac:self.deviceMac, twitter_id: twitter_id, name: name, token: self.token) { (error: Error?, success: Bool, value: Any) in
        if success {
            KRProgressHUD.dismiss()
            let json = JSON(value)
            print(json)
            if(json["token"] != "") {
                let token = json["token"].string
                let def = UserDefaults.standard
                def.set(token, forKey: "token")
                def.synchronize()

                Common.setIfTwitterLogin(login: token!)
                let homeViewController = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "HomeViewController") as! HomeViewController

                self.present(homeViewController, animated: false, completion: nil)
            } else {
                self.errorLable.text = "???? ??? ??? ??? ???? ??? ????"
            }
        } else {
            KRProgressHUD.dismiss()
            self.errorLable.text = "???? ??? ??? ??? ???? ??? ????"
            if Connectivity.isConnectedToNetwork(){
                print("Internet Connection Available!")
            }else{
                Common.showToast(messsage: "?????? ?????? ?? ?????? ?????????", view: self.view)
            }
        }
    }
}

和

class func loginWithTwitter(mac:String, twitter_id: String, name: String, token: String, completion: @escaping (_ error: Error?, _ success: Bool,_ value: Any) -> Void) {

    let loginURL = URLs.loginWithTwitter

    let loginParameters = [
        "mac": mac,
        "twitter_id": twitter_id,
        "token": token,
        "name": name]

    print(loginURL, loginParameters)
    Alamofire.request(loginURL, method: .post, parameters: loginParameters, encoding: URLEncoding.default, headers: nil)
        .responseJSON { reponse in
            switch reponse.result {
            case .failure(let error):
                print("error: ", error)
                completion(error, false, "")
            case .success(let value):
                completion(nil, true, value)
            }
    }
}

我在twitter开发者应用程序设置中设置了一个回调网址,任何人都知道这是什么问题？

Answer 1

在您的Twitter仪表板中访问:https://apps.twitter.com进入设置选项卡并添加以下回调URL.

twitterkit-<consumerKey>://

即twitterkit-4bvXXXXXXNFfOXXwrXXXXXXmT://

Answer 2

Twitter开发者更新了规则，你可以打开你的开发者网站，找到Callback URLS的设置，添加这一点：

对于 android
twittersdk://

对于 iOS，请参阅
/sf/answers/3559516341/
/sf/answers/3546380281/

这将是工作，希望解决你的问题