C++ - 从另一个类构造函数调用类构造函数

Question

所以我正在学习 C++ 课程，在一次练习中，我需要在名为“Character”的类的构造函数中使用名为“Weapon”的类的构造函数，但是每次我尝试编译代码时，它都会给我这个错误：

Character.cpp|13|error: no match for call to `(Weapon) (int&,std::__cxx11::string&)’|

即使我在 Weapon.h 中声明了这个确切的构造函数：

#ifndef WEAPON_H
#define WEAPON_H

#include <string>

class Weapon
{
public:
    Weapon();
    Weapon(int damage, std::string name);
    virtual ~Weapon();

    int GetDamage() { return m_damage; }
    void SetDamage(int val) { m_damage = val; }
    std::string GetName() { return m_name; }
    void SetName(std::string val) { m_name = val; }

private:
    int m_damage;
    std::string m_name;
};

#endif // WEAPON_H

顺便说一句，我是法国人，这是我第一次发帖，但我尽力将源代码翻译成英文，如果某些行后面有任何错误或意外含义，请见谅。这是我的 Character.cpp / Weapon.cpp / Character.h 文件。

#include "Character.h"
#include "Weapon.h"

Character::Character()
{
    m_health_points = 100;
    m_mana = 100;
}

Character::Character(int damage, std::string name)
{
    m_health_points = 100;
    m_mana = 100;
    m_weapon(damage, name);
}

Character::~Character()
{
}

---

#include "Weapon.h"

Weapon::Weapon()
{
}

Weapon::Weapon(int damage, std::string name)
{
    m_damage = damage;
    m_name = name;
}

Weapon::~Weapon()
{
}

---

#ifndef CHARACTER_H
#define CHARACTER_H

#include "Weapon.h"

class Character
{
public:
    Character();
    Character(int damage, std::string name);
    virtual ~Character();

    int GetHealthPoints() { return m_health_points; }
    void SetHealthPoints(int val) { m_health_points = val; }
    int GetMana() { return m_mana; }
    void SetMana(int val) { m_mana = val; }

private:
    int m_health_points;
    int m_mana;
    Weapon m_weapon;
};

#endif // CHARACTER_H

Answer 1

C++ 对构造函数中的成员变量初始化有特殊的构造：

Character::Character(int damage, std::string name)
  : m_weapon(damage,name),
    m_health_points(100),
    m_mana(100)  
{
}