在Swift 4中处理Firebase 5身份验证错误

Question

我们有一个最近更新到Firebase 5,Swift 4的现有项目,我们的身份验证错误处理似乎不起作用.

我在SO上找到了几个答案,但那些似乎不再适用:

错误处理

验证码

假设用户正在登录并输入有效的电子邮件和无效密码,这些密码将传递给以下代码进行身份验证

Auth.auth().signIn(withEmail: user, password: pw, completion: { (auth, error) in
    if error != nil {
        let errDesc = error?.localizedDescription
        print(errDesc!) //prints 'The password is invalid'
        let err = error!
        let errCode = AuthErrorCode(rawValue: err._code)
        switch errCode {
        case .wrongPassword: //Enum case 'wrongPassword' not found in type 'AuthErrorCode?'
            print("wrong password")
        default:
            print("unknown error")
        }
    } else {
        print("succesfully authd")
    }
})

以前,我们可以使用FIRAuthErrorCode来比较可能的错误,例如FIRAuthErrorCodeInvalidEmail,FIRAuthErrorCodeWrongPassword等,但上面发布的代码将无法编译,因为此行上的错误

case .wrongPassword:   Enum case 'wrongPassword' not found in type 'AuthErrorCode?'

奇怪的是,如果我通过打字使用自动填充

case AuthErrorCode.wr

.wrongPassword是一个可选择的选项,当选择编译器显示时

Enum case 'wrongPassword' is not a member of type 'AuthErrorCode?'

即使它是一个可选择的选项.

Answer 1

您应该通过将Error转换为NSError来处理错误代码.

  Auth.auth().signIn(withEmail: email, password: password) { (authResult, error) in
    switch error {
    case .some(let error as NSError) where error.code == AuthErrorCode.wrongPassword.rawValue:
      print("wrong password")
    case .some(let error):
      print("Login error: \(error.localizedDescription)")
    case .none:
      if let user = authResult?.user {
        print(user.uid)
      }
    }
  }