chrome.cookies.getAll 返回一个空数组

Question

我正在开发一个简单的 chrome 扩展，只需单击一下即可删除域中的所有 cookie，但由于某种原因，它不起作用。当我尝试从域中获取所有 cookie 时，它​​返回一个空数组。我究竟做错了什么？这是js脚本：

$("#fixTheCookiesButton").click(() => {
  // delete the cookies
  chrome.cookies.getAll({domain: "https://www.youtube.com"}, (cookies) => {
    console.log("deleting " + cookies.length + " cookies")
    for(var i = 0; i < cookies.length; i++){
      console.log(i + " deleted")
      chrome.cookies.remove({
        url: "https://www.youtube.com" + cookies[i].path,
        name: cookies[i].name
      })
    }
    
    // some other stuff that isn't relevant here
}

这是我的清单：

{
  "manifest_version": 2,
  "name": "FixYT",
  "version": "1.0",
  "description": "Fixes that YT cookie bug with one click",
  "browser_action": {
          "default_title": "FixYT",
          "default_popup": "popup.html"
  },
  "permissions": [
    "cookies",
    "https://www.youtube.com/",
    "*://www.youtube.com/",
    "tabs",
    "*://*/"
  ]
}

我尝试在互联网上查找，但找不到任何解决方案。

Answer 1

和permissions都是host_permissions必需的。

"permissions": [
  "cookies",
  "tabs"
],
"host_permissions": ["<all_urls>"],

Answer 2

正如isa所说，chrome.cookies仅在background.js中定义

\n

添加到清单，以便我们可以访问background.js\n\xc2\xa0中的chrome.cookies

\n

\xc2\xa0"permissions": [\n \xc2\xa0 \xc2\xa0 \xc2\xa0...\n \xc2\xa0 \xc2\xa0 \xc2\xa0 "cookies",\n \xc2\xa0 \xc2\xa0 ],\n\n

\n

背景.js

\n

...\nchrome.cookies.getAll({\n    }, function (theCookies) {\n        cookies = theCookies\n        console.log(cookies)\n    });\n\n

\n

\n

将 Cookie 从 background.js 发送到其他视图

\n

（不是必需的，但仍然有用）

\n

\n添加到 panel.js 以搜索 cookie。[当您打开扩展程序 ie（拼图图标）-> 单击您的扩展程序时，这将触发]

\n

chrome.runtime.sendMessage({ command: "GetCookies"}, \n      function(response) {\n            console.log("I received cookies!")\n            console.log(response)\n      }\n);\n

\n

添加到background.js逻辑以从浏览器获取cookie并检查已知cookie

\n

\nchrome.runtime.onMessage.addListener(function (message, sender, callback) {\n    if (message.command === \'GetCookies\') {\n        checkKnownCookies()\n    }\n});\nlet cookies = [] // Hold IDs of recognized cookies\nfunction checkKnownCookies() {\n    chrome.cookies.getAll({\n    }, function (theCookies) {\n        cookies = theCookies\n        console.log(cookies)\n        callback(theCookies)\n    });\n}\n\xc2\xa0\n

\n

https://developer.chrome.com/docs/extensions/reference/cookies/#method-getAll

\n

要查看 background.js 的控制台，请转到（拼图图标）-> 管理扩展，然后单击指向您的扩展的 background.html 的 href 链接

\n

Answer 3

你应该在background.js中调用这个代码块

    chrome.cookies.getAll({
  domain: ".youtube.com"
}, function (cookies) {
  for (var i = 0; i < cookies.length; i++) {
    console.log(cookies[i] + "deleted");
    chrome.cookies.remove({
      url: "https://" + cookies[i].domain + cookies[i].path,
      name: cookies[i].name
    });
  }
});