Nei*_*ght 6 sql sql-server-2008
我有一个使用该IN子句的查询.这是一个简化版本:
SELECT *
FROM table A
JOIN table B
ON A.ID = B.ID
WHERE B.AnotherColumn IN (SELECT Column FROM tableC WHERE ID = 1)
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tableC没有Column列,但查询执行得很好,没有错误消息.有谁能解释为什么?
Mat*_*son 14
如果外部查询中的表具有该名称的列,则此方法将起作用.这是因为外部查询中的列名可用于子查询,您可能故意在子查询SELECT列表中选择外部查询列.
例如:
CREATE TABLE #test_main (colA integer)
CREATE TABLE #test_sub (colB integer)
-- Works, because colA is available to the sub-query from the outer query. However,
-- it's probably not what you intended to do:
SELECT * FROM #test_main WHERE colA IN (SELECT colA FROM #test_sub)
-- Doesn't work, because colC is nowhere in either query
SELECT * FROM #test_main WHERE colA IN (SELECT colC FROM #test_sub)
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正如Damien观察到的那样,保护自己免受这种不太明显的"陷阱"的最安全的方法是养成在子查询中限定列名的习惯:
-- Doesn't work, because colA is not in table #test_sub, so at least you get
-- notified that what you were trying to do doesn't make sense.
SELECT * FROM #test_main WHERE colA IN (SELECT #test_sub.colA FROM #test_sub)
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