重新排序modelform字段

Question

我需要重新排序来自另一个基类的模型中的字段.无法找到解决方案.下面代码段中的"地址"始终显示在HTML模板的开头.如何使用渲染模板进一步向下移动？提前致谢.

class Address:
   street= ...
   city= ...

class Customer(Address):
   name = ...
   ...

class CustomerForm(ModelForm):
   def __init__(...)
        super(CustomerForm, self).__init__(*args, **kw)
        self.fields.keyOrder=[
        'name',
        'Address',  #<-- I want "Address" appear after the name in my template
                    #<-- This obviously is not the right code.
   class Meta:
      model = Customer

-P

Answer 1

重新订购非常繁琐:

# django's SortedDict stores ordering of its fields in this list-type attribute:
keyorder = self.fields.keyOrder

# Remove fields which we want to displace:
keyorder.remove('street')
keyorder.remove('city')

# Get position where we want them to put in:
i = keyorder.index('name') + 1

# Insert items back into the list:
keyorder[i:i] = ['city', 'street']

可能更好的方法是再次以正确的顺序列出所有字段:

class MyForm(ModelForm):
    class Meta:
       model=Customer
       fields=[..., 'name', 'street', 'city', ...]

Answer 2

在Django 1.9中,他们向Form类添加新参数现在您可以通过定义field_order来更改顺序 ,例如添加两个字段来使用应用程序表单:

class SignupFormExtra(SignupForm):
    """
    A form to demonstrate how to add extra fields to the signup form, in this
    case adding the first and last name.
    """
    first_name = forms.CharField(label=_(u'First name'),
                             max_length=30,
                             required=False)

    last_name = forms.CharField(label=_(u'Last name'),
                            max_length=30,
                            required=False)
    field_order=['first_name','last_name']

您可以将它用于任何继承类Form的表单.

默认情况下,Form.field_order = None,它保留您在表单类中定义字段的顺序.如果field_order是字段名称列表,则按列表指定的顺序排序字段,并根据默认顺序追加其余字段.

Answer 3

from django import forms

class CustomForm(forms.Form):
    ORDER = ('field1', 'field2', 'field3')
    def __init__(self, *args, **kwargs):
        super(CustomForm, self).__init__(*args, **kwargs)
        fields = OrderedDict()
        for key in self.ORDER:
            fields[key] = self.fields.pop(key)
        self.fields = fields