aid*_*181 5 serialization android kotlin firebase data-class
嗨我有一个Kotlin数据类如下
data class User (
@get:Exclude val gUser: Boolean,
@get:Exclude val uid: String,
@get:PropertyName("display_name") val displayName: String,
@get:PropertyName("email") val email: String,
@get:PropertyName("account_picture_url") val accountPicUrl: String,
@get:PropertyName("provider") val provider: String
)
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我能够没有问题地序列化对象.但是在执行firebase查询时,我无法反序列化对象.目前这是我正在做的获取数据
_firebaseReference.child(getString(R.string.firebase_users_key)).child(user.uid)
.setValue(user).addOnCompleteListener{
_firebaseReference.child("users").child(user.uid)
.addListenerForSingleValueEvent(object : ValueEventListener {
override fun onCancelled(p0: DatabaseError) {
}
override fun onDataChange(p0: DataSnapshot) {
if (p0.exists()) {
val userHash = p0.value as HashMap<*, *>
var currentUser: User
if (userHash[getString(R.string.provider_key)]
!= getString(R.string.provider_google)) {
currentUser = User(false, p0.key!!,
userHash["display_name"].toString(),
userHash["email"].toString(),
userHash["account_picture_url"].toString(),
userHash["provider"].toString())
} else {
currentUser = User(true, p0.key!!,
userHash["display_name"].toString(),
userHash["email"].toString(),
userHash["account_picture_url"].toString(),
userHash["provider"].toString())
}
}
}
})
}
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这只是我正在努力练习我的Kotlin的一个测试项目,但这是我想要弄清楚的.
如果我完全错误请告诉我,任何建议将不胜感激
谢谢
Lev*_*ira 14
Firebase需要一个空构造函数才能反序列化对象:
data class User(
@Exclude val gUser: Boolean,
@Exclude val uid: String,
@PropertyName("display_name") val displayName: String,
@PropertyName("email") val email: String,
@PropertyName("account_picture_url") val accountPicUrl: String,
@PropertyName("provider") val provider: String
) {
constructor() : this(false, "", "", "", "", "")
}
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您可以像这样声明它并提供一些默认值以便能够调用主构造函数,或者您可以为所有参数声明默认值:
data class User (
@Exclude val gUser: Boolean = false,
@Exclude val uid: String = "",
@PropertyName("display_name") val displayName: String = "",
@PropertyName("email") val email: String = "",
@PropertyName("account_picture_url") val accountPicUrl: String = "",
@PropertyName("provider") val provider: String = ""
)
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然后将为您创建各种构造函数,包括一个空构造函数.
如果序列化存在问题,可能是因为ide生成的getter和setter,请尝试使用@get和@set注释加强它们:
data class User (
@Exclude val gUser: Boolean = false,
@Exclude val uid: String = "",
@set:PropertyName("display_name")
@get:PropertyName("display_name")
var displayName: String = "",
@PropertyName("email") val email: String = "",
@set:PropertyName("account_picture_url")
@get:PropertyName("account_picture_url")
var accountPicUrl: String = "",
@PropertyName("provider") val provider: String = ""
)
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