Hac*_*ode 3 javascript arrays asynchronous
我正在尝试获取某些数组元素的值。它适用于元素 [0]、[1]、[2]、[3],但不适用于 [4]。
function getBase64() {
const urls = ['https://i.imgur.com/egNg7JU.jpg',
'https://i.imgur.com/RLZ7WH1.jpg', 'https://i.imgur.com/qfabBbA.jpg',
'https://i.imgur.com/Zuh1KaX.jpg', 'https://i.imgur.com/yD7X6Q1.jpg'
];
let base64urls = [];
const start = async () => {
await asyncForEach(urls, async (num) => {
await waitFor(50)
toDataURL(num, function(dataURL) {
base64urls.push(dataURL);
});
})
console.log(base64urls);
console.log(base64urls[4]);
}
start()
}
async function asyncForEach(array, callback) {
for (let index = 0; index < array.length; index++) {
await callback(array[index], index, array)
}
}
const waitFor = (ms) => new Promise(r => setTimeout(r, ms))
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toDataURL简单地返回图像的 base64 值。每当我尝试console.log(base64urls[4]),它都会返回“未定义”。我确实得到了前面元素的正确值。有什么方法可以重构它,或者使用不同的方法来等待数组完全填充,然后再检查其元素的值?
编辑
这是我的 toDataURL
function toDataURL(src, callback) {
const image = new Image();
image.crossOrigin = 'Anonymous';
image.onload = function () {
const canvas = document.createElement('canvas');
const context = canvas.getContext('2d');
canvas.height = this.naturalHeight;
canvas.width = this.naturalWidth;
context.drawImage(this, 0, 0);
const dataURL = canvas.toDataURL('image/jpeg');
callback(dataURL);
};
image.src = src;
}
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看起来toDataURL是异步的,回调为主-要么改变它,以便它返回一个Promise和await那Promise,或传递Promise的resolve步入回调:
async function getBase64() {
const urls = ['https://i.imgur.com/egNg7JU.jpg',
'https://i.imgur.com/RLZ7WH1.jpg', 'https://i.imgur.com/qfabBbA.jpg',
'https://i.imgur.com/Zuh1KaX.jpg', 'https://i.imgur.com/yD7X6Q1.jpg'];
const base64urls = [];
for (const url of urls) {
const dataURL = await new Promise(resolve => toDataURL(url, resolve));
base64urls.push(dataURL);
}
console.log(base64urls);
console.log(base64urls[4]);
}
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如果您想更改您的toDataURL函数以返回一个 Promise,那么您不必将其视为回调:
function toDataURL(src) {
return new Promise(resolve => {
const image = new Image();
image.crossOrigin = 'Anonymous';
image.onload = function () {
const canvas = document.createElement('canvas');
const context = canvas.getContext('2d');
canvas.height = this.naturalHeight;
canvas.width = this.naturalWidth;
context.drawImage(this, 0, 0);
const dataURL = canvas.toDataURL('image/jpeg');
resolve(dataURL);
};
image.src = src;
});
}
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进而 const dataURL = await toDataURL(url)
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