更好地初始化一副牌的方法

Question

有没有更简单的方法来执行此操作,而不是手动将每个元素插入到数组中

stack_of_cards << Card.new("A", "Spades", 1)
stack_of_cards << Card.new("2", "Spades", 2)
stack_of_cards << Card.new("3", "Spades", 3)
stack_of_cards << Card.new("4", "Spades", 4)
stack_of_cards << Card.new("5", "Spades", 5)
stack_of_cards << Card.new("6", "Spades", 6)
stack_of_cards << Card.new("7", "Spades", 7)
stack_of_cards << Card.new("8", "Spades", 8)
stack_of_cards << Card.new("9", "Spades", 9)
stack_of_cards << Card.new("10", "Spades", 10)
stack_of_cards << Card.new("J", "Spades", 11)
stack_of_cards << Card.new("Q", "Spades", 12)
stack_of_cards << Card.new("K", "Spades", 13)

stack_of_cards << Card.new("A", "Hearts", 1)
stack_of_cards << Card.new("2", "Hearts", 2)
stack_of_cards << Card.new("3", "Hearts", 3)
stack_of_cards << Card.new("4", "Hearts", 4)
stack_of_cards << Card.new("5", "Hearts", 5)
stack_of_cards << Card.new("6", "Hearts", 6)
stack_of_cards << Card.new("7", "Hearts", 7)
stack_of_cards << Card.new("8", "Hearts", 8)
stack_of_cards << Card.new("9", "Hearts", 9)
stack_of_cards << Card.new("10", "Hearts", 10)
stack_of_cards << Card.new("J", "Hearts", 11)
stack_of_cards << Card.new("Q", "Hearts", 12)
stack_of_cards << Card.new("K", "Hearts", 13)

stack_of_cards << Card.new("A", "Diamonds", 1)
stack_of_cards << Card.new("2", "Diamonds", 2)
stack_of_cards << Card.new("3", "Diamonds", 3)
stack_of_cards << Card.new("4", "Diamonds", 4)
stack_of_cards << Card.new("5", "Diamonds", 5)
stack_of_cards << Card.new("6", "Diamonds", 6)
stack_of_cards << Card.new("7", "Diamonds", 7)
stack_of_cards << Card.new("8", "Diamonds", 8)
stack_of_cards << Card.new("9", "Diamonds", 9)
stack_of_cards << Card.new("10", "Diamonds", 10)
stack_of_cards << Card.new("J", "Diamonds", 11)
stack_of_cards << Card.new("Q", "Diamonds", 12)
stack_of_cards << Card.new("K", "Diamonds", 13)

stack_of_cards << Card.new("A", "Clubs", 1)
stack_of_cards << Card.new("2", "Clubs", 2)
stack_of_cards << Card.new("3", "Clubs", 3)
stack_of_cards << Card.new("4", "Clubs", 4)
stack_of_cards << Card.new("5", "Clubs", 5)
stack_of_cards << Card.new("6", "Clubs", 6)
stack_of_cards << Card.new("7", "Clubs", 7)
stack_of_cards << Card.new("8", "Clubs", 8)
stack_of_cards << Card.new("9", "Clubs", 9)
stack_of_cards << Card.new("10", "Clubs", 10)
stack_of_cards << Card.new("J", "Clubs", 11)
stack_of_cards << Card.new("Q", "Clubs", 12)
stack_of_cards << Card.new("K", "Clubs", 13)

Answer 1

只需循环两个级别和套装.

ranks = %w{A 2 3 4 5 6 7 8 9 10 J Q K}
suits = %w{Spades Hearts Diamonds Clubs}
suits.each do |suit|
  ranks.size.times do |i|
    stack_of_cards << Card.new( ranks[i], suit, i+1 )
  end
end