Gre*_*han 2 php security authentication api symfony
使用下面列出的这个配置,我遇到了一些我无法单独解决的奇怪问题,因为我在 Symfony 中太新了。
security:
encoders:
App\Api\User\Entity\User:
algorithm: bcrypt
cost: 12
# https://symfony.com/doc/current/security.html#where-do-users-come-from-user-providers
providers:
users:
id: 'App\Api\Auth\Provider\AuthProvider'
firewalls:
dev:
pattern: ^/(_(profiler|wdt)|css|images|js)/
security: false
# Api will be stateless, a token will be generated
api_login:
pattern: /api/login
stateless: true
context: api
anonymous: true
provider: users
form_login:
check_path: /api/login
username_parameter: email
password_parameter: password
success_handler: lexik_jwt_authentication.handler.authentication_success
failure_handler: lexik_jwt_authentication.handler.authentication_failure
require_previous_session: false
# For web calls no need to be stateless
web_login:
pattern: /login
stateless: false
context: web
anonymous: true
provider: users
guard:
entry_point: 'App\User\Auth\Guard\LoginAuthenticator'
authenticators:
- 'App\Api\Auth\Guard\LoginAuthenticator'
form_login:
login_path: /login
check_path: /login
api:
provider: users
context: api
pattern: ^/api
stateless: true
anonymous: true
guard:
authenticators:
- lexik_jwt_authentication.jwt_token_authenticator
web:
provider: users
context: web
pattern: ^(/user|/template)
stateless: false
anonymous: true
guard:
authenticators:
- 'App\Api\Auth\Guard\LoginAuthenticator'
main:
pattern: ^/
anonymous: ~
logout:
path: /logout
target: /login
# Easy way to control access for large sections of your site
# Note: Only the *first* access control that matches will be used
access_control:
- { path: ^/api, roles: ROLE_USER }
- { path: ^/user/*, roles: ROLE_USER }
- { path: ^/login, roles: IS_AUTHENTICATED_ANONYMOUSLY }
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我有 :
现在这是什么工作:
当我连接 (HTML) 时,我会立即重定向到 /user/profile 端点并查看我的信息
我可以调用我的 API 登录端点并获取 JWT 令牌
这里有什么不工作
我解码的令牌:
Run Code Online (Sandbox Code Playgroud){"alg":"RS256"}{"roles":["ROLE_USER"],"username":null,"iat":1527787676,"exp":1527791276}
错误:
{
"code": 401,
"message": "Unable to find key \"username\" in the token payload."
}
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任何的想法 ?
我的身份字段是电子邮件,而不是用户名。
在 jwt 配置文件中,我只需要输入:
lexik_jwt_authentication:
private_key_path: '%kernel.project_dir%/%env(JWT_PRIVATE_KEY_PATH)%'
public_key_path: '%kernel.project_dir%/%env(JWT_PUBLIC_KEY_PATH)%'
pass_phrase: '%env(JWT_PASSPHRASE)%'
user_identity_field: email #this line
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